3/(<em>x</em> ² - 1) = 3/((<em>x</em> - 1) (<em>x</em> + 1)) = <em>a</em>/(<em>x</em> - 1) + <em>b</em>/(<em>x</em> + 1)
==> 3 = <em>a</em> (<em>x</em> + 1) + <em>b</em> (<em>x</em> - 1)
==> 3 = (<em>a</em> + <em>b</em>) <em>x</em> + <em>a</em> - <em>b</em>
==> <em>a</em> + <em>b</em> = 3 and <em>a</em> - <em>b</em> = 0
==> <em>a</em> = <em>b</em>
==> <em>a</em> + <em>b</em> = 2<em>a</em> = 3 ==> <em>a</em> = 2/3 and <em>b</em> = 2/3
So you have
3/(<em>x</em> ² - 1) = 2/(3(<em>x</em> - 1)) + 2/(3(<em>x</em> + 1))
Answer: it is
Step-by-step explanation: the next numbers are 1.5, 3, 4.5.
Answer:
c) (3-7x^2)(x-3)
Step-by-step explanation:
-7x^3+21x^2+3x-9
Factor out a -7x^2 from the first two terms and a 3 from the last two terms
-7x^2 (x -3) +3(x-3)
Now factor out (x-3)
(x-3) (-7x^2+3)
Rearranging)
(x-3) (3-7x^2)
Holding what.......? can u be more specific?
If you think about it, the question is asking us to find the greatest common factor, or GCF, of the two numbers, 24 and 18.
First, find all of the factors of 24.
The factors are: 1, 2, 3, 4, 6, 8, 12, 24
Next, find the factors of 18.
The factors are: 1, 2, 3, 6, 9, 18
List out all of the factors that both of the numbers have.
The factors are: 1, 2, 3, 6
Whichever is the greatest of these numbers is the GCF.
The GCF is 6, so the greatest number of groups he can make and still be able to win is 6.
Hope this helps!
