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Artist 52 [7]
4 years ago
10

We examined the relationship between Rotten Tomatoes ratings and Metascore ratings for a sample of 75 popular movies. The scatte

rplot showed a linear form with strong positive association. Here is are the StatCrunch linear regression results. The r-sq value is about 0.75. What does this tell us? Simple linear regression results: Dependent Variable: Metascore Independent Variable: Rotten Tomatoes Metascore 21.605526+0.62434658 Rotten Tomatoes Sample size: 72 R (correlation coefficient) 0.86590 102 R-sq 0.74978458 Estimate of error standard deviation: 7.7978789a. 75 % of the Metascore ratings are accurately predicted by the regression line. b. Rotten Tomato ratings explain about 75 % of the variation in Metascore ratings.c. For each one point increase in Rotten Tomato ratings, we predict a 0.75 point increase in Metascore ratings.
Mathematics
1 answer:
3241004551 [841]4 years ago
7 0

Answer:

Therefore Rotten Tomato ratings explain about 75% of the variation in Metascore ratings is the correct answer here.

Step-by-step explanation:

The R2 value for regression or the coefficient of determination represents the proportion of variation in dependent variable that is explained by regression ( the rest of it is residual variation )

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Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

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A lighthouse is located on a small island 2 km away from the nearest point P on a straight shoreline and its light makes four re
ddd [48]

Answer:

62.8 km per min

Step-by-step explanation:

Let the diagram of this situation is shown below,

In which \theta is the angle made by light to the straight line joining the lighthouse and P,

∵ Light makes 4 revolutions per minute.

Also, 1 revolution = 2\pi radians

So, the change in angle with respect to t ( time ),

\frac{d\theta}{dt}=8\pi\text{ radians per min}

Let x be the distance of beam from P,

\implies \tan \theta = \frac{x}{2}

Differentiating with respect to x,

\sec^2 \theta \frac{d\theta}{dt}=\frac{1}{2}\frac{dx}{dt}

(1+\tan^2 \theta) (8\pi) = \frac{1}{2}\frac{dx}{dt}

(1+\frac{x^2}{2^2})(8\pi) = \frac{1}{2}\frac{dx}{dt}

If x = 1 km,

(1+\frac{1}{4})8\pi =\frac{1}{2}\frac{dx}{dt}

\frac{5}{4}8\pi = \frac{1}{2}\frac{dx}{dt}

\implies \frac{dx}{dt}=\frac{80\pi}{4}= 20\pi\approx 62.8\text{ km per min}

Hence, the beam of light moving along the shoreline with the speed of 62.8 km per min

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