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Artist 52 [7]
3 years ago
10

We examined the relationship between Rotten Tomatoes ratings and Metascore ratings for a sample of 75 popular movies. The scatte

rplot showed a linear form with strong positive association. Here is are the StatCrunch linear regression results. The r-sq value is about 0.75. What does this tell us? Simple linear regression results: Dependent Variable: Metascore Independent Variable: Rotten Tomatoes Metascore 21.605526+0.62434658 Rotten Tomatoes Sample size: 72 R (correlation coefficient) 0.86590 102 R-sq 0.74978458 Estimate of error standard deviation: 7.7978789a. 75 % of the Metascore ratings are accurately predicted by the regression line. b. Rotten Tomato ratings explain about 75 % of the variation in Metascore ratings.c. For each one point increase in Rotten Tomato ratings, we predict a 0.75 point increase in Metascore ratings.
Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

Therefore Rotten Tomato ratings explain about 75% of the variation in Metascore ratings is the correct answer here.

Step-by-step explanation:

The R2 value for regression or the coefficient of determination represents the proportion of variation in dependent variable that is explained by regression ( the rest of it is residual variation )

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Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

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Formula:

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P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%

P(20 \leq x \leq 30) = 55.88\%

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

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c) P(mean score of sample is between 20 and 30)

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balandron [24]
Simplifying the above expression we shall proceed as follows:
<span>x-2/(x^2+4x-12)
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</span>x^2+4x-12
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Answer: 1/(x+6)
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