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<u><em>Answer:</em></u>s = 22°
<u><em>Explanation:</em></u><u>1- getting the top right angle of line B:</u>We are given that:
the top right angle of line A = 158°
Since lines A and B are parallel, therefore, the top right angle of line A and the top right angle of line B are corresponding angles which means that they are equal
This means that:
<u>Top right angle of line B = 158°</u>
<u>2- getting the value of s:</u>Now, taking a look at line B, we can note that:
angle s and the top right angle form a straight angle. This means that the sum of these two angles is 180°
Therefore:
180 = s + 158
s = 180 - 158
<u>s = 22°</u>
Hope this helps :)
L(1, -4)=(xL, yL)→xL=1, yL=-4
M(3, -2)=(xM, yM)→xM=3, yM=-2
Slope of side LM: m LM = (yM-yL) / (xM-xL)
m LM = ( -2 - (-4) ) / (3-1)
m LM = ( -2+4) / (2)
m LM = (2) / (2)
m LM = 1
The quadrilateral is the rectangle KLMN
The oposite sides are: LM with NK, and KL with NK
In a rectangle the opposite sides are parallel, and parallel lines have the same slope, then:
Slope of side LM = m LM = 1 = m NK = Slope of side NK
Slope of side NK = m NK = 1
Slope of side KL = m KL = m MN = Slope of side MN
The sides KL and LM (consecutive sides) are perpendicular (form an angle of 90°), then the product of their slopes is equal to -1:
(m KL) (m LM) = -1
Replacing m LM = 1
(m KL) (1) = -1
m KL = -1 = m MN
Answer:
Slope of side LM =1
Slope of side NK =1
Slope of side KL = -1
Slope of side MN = -1
Answer:
forst find the area of the whole rectangle and then the area of the unshaded triangles then add the area of the two triangle and subtract it with the area of the rectange
Step-by-step explanation: area of rectangle is length × breadth and area of triangle is 1/2 × base × height
5 * 2 = 10
3^10/3^-2, same base, add
10 - 2 = 8
Solution: 10^8
The weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs
<h3>How to determine the weights?</h3>
The given parameters are:
- Mean, μ = 9.5
- Standard deviation, σ = 0.5
The weights within 2 standard deviation is represented as:
μ - 2σ ≤ x ≤ μ + 2σ
Substitute known values
9.5 - 2(0.5) ≤ x ≤ 9.5 + 2(0.5)
Evaluate the product
9.5 - 1 ≤ x ≤ 9.5 + 1
Evaluate the sum
8.5 ≤ x ≤ 10.5
This means that the weights are between 8.5 and 10.5 (inclusive)
Hence, the weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs
Read more about standard deviation at:
brainly.com/question/11743583