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zubka84 [21]
3 years ago
10

How much longer is the distance from the library to the park to the train station than the distance from the library straight to

the train station?
Library to train station 3.82 mi
Train station to the park 2.96 mi
Park to the library 2.14 mi
Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

2.14

Step-by-step explanation:

2.14+3.82= 5.96

5.96-3.82= 2.14

So, your answer would be 2.14

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(x+2) (x+3)

Step-by-step explanation:

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3 years ago
8) Tammy uses 1 3/4 cups of laundry detergent per load. When she was finished
mina [271]

Tammy uses 1 3/4 cups of laundry detergent. The number of loads is 4

<u>Solution:</u>

Given that, Tammy uses 1 3/4 cups of laundry detergent per load.  

When she was finished doing laundry one day.  

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We have to find how many loads did she do?

Now, we know that, Total cups used can be written as:

<em> </em>number of loads x number of cups per each load = total cups used.

\begin{array}{l}{\text { Then, number of loads } \times 1 \frac{3}{4}=7} \\\\ {\text { Number of loads } \times \frac{1 \times 4+3}{4}=7} \\\\ {\text { Number of loads } \times \frac{7}{4}=7} \\\\ {\text { Number of loads }=7 \times \frac{4}{7}=4}\end{array}

Hence, the number of loads are 4.

6 0
3 years ago
A company will need 1.8 million 5 years from now to replace some equipment. Currently, the firm has some extra cash and would li
Nezavi [6.7K]

Given:

a.) A company will need 1.8 million 5 years from now to replace some equipment.

b.) The account pays 5.25 percent interest, compounded annually.

We will be applying the Compounded Interest Formula:

\text{ A = P\lparen1 + }\frac{r}{n})^{nt}

Where,

A=final amount

P=initial principal balance/money to initially deposit

r=interest rate (decimal)

n=number of times interest applied per time period

t=number of time periods elapsed (in years)

In this scenario, we are asked what is the amount of principal balance/initial deposit to make to get 1.8 million in 5 years.

Annually = n = 1

We get,

\text{ 1,800,000 = P\lparen1 + }\frac{\frac{5.25}{100}}{1})^{(1)(5)}1,800,000\text{ = P \lparen1 + 0.0525\rparen}^5\text{ = P \lparen1.0525\rparen}^5\text{ P = }\frac{1,800,000}{(1.0525)^5}\text{ P = 1,393,676.5175887556 }\approx\text{ 1,393,676.52}

Therefore, the answer is 1,393,676.52

5 0
1 year ago
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Wittaler [7]

Answer:

7 is in the ten-thousands place.

Step-by-step explanation:

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3 years ago
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