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zubka84 [21]
2 years ago
10

How much longer is the distance from the library to the park to the train station than the distance from the library straight to

the train station?
Library to train station 3.82 mi
Train station to the park 2.96 mi
Park to the library 2.14 mi
Mathematics
1 answer:
Slav-nsk [51]2 years ago
7 0

Answer:

2.14

Step-by-step explanation:

2.14+3.82= 5.96

5.96-3.82= 2.14

So, your answer would be 2.14

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Multiply.<br><br> (2 − 5i)(3 + i)
ANEK [815]

(2-5i)(3+i)

use foil method to expand it into standard form

6+2i-15i+5i^2

5i^2-13i+6

7 0
3 years ago
The beginning checkbook balance of Gregory Co. was $3,045.58. Their bank statement indicated a balance of $4,262.92. The bookkee
Alex_Xolod [135]

Answer:

$3,659.82

Step-by-step explanation:

Adding to the checkbook those debits and credits not already there brings its balance to ...

... $3045.58 +651.84 -37.60 = $3659.82

Adjusting the bank's balance by the deposits and checks not already there brings its balance to ...

... $4262.92 +220.05 -325.50 -497.65 = $3659.82

Thus, the reconciled accounts will agree on the balance $3659.82.

8 0
3 years ago
What’s pemdas and how do we use it ?
Gwar [14]

Answer:

pemdas is an order of operation

Step-by-step explanation:

PEMDAS STANDS FOR parentheis, exponents, multiplication, division, addition, and subtraction. it is the order of how you should solve multi step equations EXAMPLE: 1+2x2 FIRST you have to multiply the 2x2 because multiplication comes first in PEMDAS, then you do the addition so 2x2=4+1=5

3 0
3 years ago
What is 20,700,0000 in standard notation?
alexdok [17]

Answer:

2.07 x 10^4

Step-by-step explanation:

8 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
3 years ago
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