Question

Three consecutive even numbers have a sum where one half of that sum is between 90 and 105.

Answer 1

$n;\ n+2;\ n+4-three\ consecutive\ even\ numbers\\\\90 \ \textless \ \dfrac{1}{2}(n+n+2+n+4) \ \textless \ 105\\\\90 \ \textless \ \dfrac{1}{2}(3n+6) \ \textless \ 105\ \ \ |multiply\ both\ sides\ by\ 2\\\\180 \ \textless \ 3n+6 \ \textless \ 210\ \ \ |subtract\ 6\ from\ both\ sides\\\\174 \ \textless \ 3n \ \textless \ 204\ \ \ |divide\ both\ sides\ by\ 3\\\\58 \ \textless \ n \ \textless \ 68\\\\Answer:\\60;\ 62;\ 64\ or\ 62;\ 64;\ 66;\ or\ 64;\ 66;\ 68\ or\ 66;\ 68;\ 70.$