Three consecutive even numbers have a sum where one half of that sum is between 90 and 105.

1 answer:

5 0

$n;\ n+2;\ n+4-three\ consecutive\ even\ numbers\\\\90 \ \textless \ \dfrac{1}{2}(n+n+2+n+4) \ \textless \ 105\\\\90 \ \textless \ \dfrac{1}{2}(3n+6) \ \textless \ 105\ \ \ |multiply\ both\ sides\ by\ 2\\\\180 \ \textless \ 3n+6 \ \textless \ 210\ \ \ |subtract\ 6\ from\ both\ sides\\\\174 \ \textless \ 3n \ \textless \ 204\ \ \ |divide\ both\ sides\ by\ 3\\\\58 \ \textless \ n \ \textless \ 68\\\\Answer:\\60;\ 62;\ 64\ or\ 62;\ 64;\ 66;\ or\ 64;\ 66;\ 68\ or\ 66;\ 68;\ 70.$

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Step-by-step explanation:

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3 years ago

Solve the system by substitution.<br> y = -7x. y = -5x + 10

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Step-by-step explanation:

-7x=-5x+10

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3 years ago

Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products