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Levart [38]
3 years ago
11

Which of the following is a monomial? 12c c2 − 16 c2 + c + 6 c3 + 4c2 − 12c + 7

Mathematics
2 answers:
scoray [572]3 years ago
4 0
12c because monomials only consist of one term.
dlinn [17]3 years ago
3 0

Answer:

12c

Step-by-step explanation:


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The ratio of boys to girls in Mr. Smith's class is 3:2.
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Answer: A and E

Step-by-step explanation: since the question says boys to girls and not girls to boys we assume the first number in the ratio is boys. This makes A correct 3 boys for every 2 girls. And 3+2 is 5 so for every 5 students there are 2 girls because you add the 3 boys

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1/4 plus 1/5 plus 11/12
Nataly_w [17]

Answer: 41/30

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1/4 + 1/5 + 11/12 = 41/30 ( 1.36 in alternative form )

***If you found my answer helpful, please give me the brainliest, please give a nice rating, and the thanks ( heart icon :) ***

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3 years ago
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One box of cake mix makes a maximum of 24 cupcakes. If the caterer needs 300 cupcakes for the event, what is the minimum number
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12 and a half, or more likely, 13
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The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?
Lina20 [59]
\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
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\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right)  (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right)  (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right)  ((xy)^2+2xy+1) = 0
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\\2y\ y' + \left(3y+3x\ y'\right)  ((xy)^2+2xy+1) = 0
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\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
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\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y


y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
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\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
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7 0
3 years ago
Combine like terms,<br><br> 1)c+19-4<br><br> 2)m+12-10
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1) Would be c+15 because you can combine 19-4

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8 0
3 years ago
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