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Musya8 [376]
3 years ago
11

A spinner has 10 equally sized sections, 5 of which are gray and 5 of which are blue. The spinner is spun twice. What is the pro

bability that the first spin lands on gray and the second spin lands on blue? Write your answer as a fraction in the simplest form.
Mathematics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

P(Gray\ and\ Blue) = \frac{1}{4}

Step-by-step explanation:

Given

Sections = 10

n(Gray) = 5

n(Blue) = 5

Required

Determine P(Gray and Blue)

Using probability formula;

P(Gray\ and\ Blue) = P(Gray) * P(Blue)

Calculating P(Gray)

P(Gray) = \frac{n(Gray)}{Sections}

P(Gray) = \frac{5}{10}

P(Gray) = \frac{1}{2}

Calculating P(Gray)

P(Blue) = \frac{n(Blue)}{Sections}

P(Blue) = \frac{5}{10}

P(Blue) = \frac{1}{2}

Substitute these values on the given formula

P(Gray\ and\ Blue) = P(Gray) * P(Blue)

P(Gray\ and\ Blue) = \frac{1}{2} * \frac{1}{2}

P(Gray\ and\ Blue) = \frac{1}{4}

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