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3 years ago

Aswer to expand 3(n+7)

Mathematics

2 answers:

Yakvenalex [24]3 years ago

6 0

3n+21 because of distributive property.

Charra [1.4K]3 years ago

5 0

3n + 21
n=7
................

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State the system of linear inequalities which satisfies the following shaded regions. help ??asappp

7nadin3 [17]

Find the equation of the line that does not have an equation written for it.

(4, -4) (0,-2)

m = (-2 + 4) / (0 - 4)

m = 2 / -4 = -1/2

y = -1/2x - 2

Let's now look at all of these different lines we have. For the two intersecting lines, we know that the bottom one must be greater than and the top must be less than. And because these are solid lines, they are greater/less than or equal to. For the dotted line, we know that x must be less than because the line is dotted and the shading is to the left.

y ≤ x - 2

x < 4

y ≥ -1/2x - 2

Hope this helps! :)

6 0

3 years ago

Jason deposits $5 into his savings account twice a week for 6 weeks. How much money will he have saved after 6 weeks?

gregori [183]

Answer:

$60

The equation is x(5(2))=s or x(10)=s when x = number of weeks

Step-by-step explanation:

For 6 weeks, all you have to do is plug in the 6 where the x is.

6(5(2)) = s

6(10) = s

60 = s

6(10) = s

60 = s

8 0

3 years ago

Students in a representative sample of 69 second-year students selected from a large university in England participated in a stu

Serhud [2]

Answer:

95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].

Step-by-step explanation:

We are given that for the 69 second-year students in the study at the university, the sample mean procrastination score was 41.00 and the sample standard deviation was 6.89.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean procrastination score = 41

s = sample standard deviation = 6.89

n = sample of students = 69

$\mu$ = population mean estimate

Here for constructing 95% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.9973 < $t_6_8$ < 1.9973) = 0.95 {As the critical value of t at 68 degree

of freedom are -1.9973 & 1.9973 with P = 2.5%}

P(-1.9973 < $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ < 1.9973) = 0.95

P( $-1.9973 \times{\frac{s}{\sqrt{n} } }$ < ${\bar X -\mu}$ < $1.9973 \times{\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.9973 \times{\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.9973 \times{\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ =[ $\bar X-1.9973 \times{\frac{s}{\sqrt{n} } }$ , $\bar X+1.9973 \times{\frac{s}{\sqrt{n} } }$ ]

= [ $41-1.9973 \times{\frac{6.89}{\sqrt{69} } }$ , $41+1.9973 \times{\frac{6.89}{\sqrt{69} } }$ ]

= [39.34 , 42.66]

Therefore, 95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].

5 0

3 years ago

Ty is 3 years younger than bea. what would the equation be?

Alexandra [31]

T = B + 3 T = B - 3 T = 3 - B T = 3B

6 0

3 years ago

If a and b are positive integers and 22a(22b)=16, what is the value of a+b?

Kryger [21]

Given that:
22a(22b)=16
484ab=16
thus
ab=16/484
ab=4/121
thus given that
ab=4/121
then
a=4 and b=1/121
hence
4+1/121
=4 1/121

8 0

3 years ago