25x^2+10x+1
25x^2+5x+5x+1
5x(5x+1)+1(5x+1)
(5x+1)(5x+1)
(5x+1)^2
In my work I used t=trains and m=minutes:
30+30= 60m/2t
<span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
Total= 720m/24t
1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30= 4 o' clock
Total= 372m/12t
24t+12t= 36t
The answer is:
36 trains in total</span>
165/1,000 is .165 in fraction form.
A is the correct choice.
This is based on the vertical line test. If you were to draw an imaginary vertical line on the graph, it would only intersect the graph at one point, which proves that all x values are different (a function).
Answer:
hope this helps you in some way
