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swat32
3 years ago
14

I need help on this question

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

Hello!

In a taxi cab, the longer you ride, the more it costs. This would make a scatter plot go through Quadrant 1.

Therefore, it would have a positive relationship

I hope this helps!

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The sum of two numbers must be 14 or greater. The product of the two numbers must be less than 40. Which system of inequalities
Anettt [7]

Answer:

A

Step-by-step explanation:

x+y≥14

xy<40

4 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
Day 6: Textbook Page 321 Problem 9 When Esteban looks at the puddle, he sees a reflection of the top of the cactus. How tall is
Novay_Z [31]

The given figure can be drawn as,

From the figure,

\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}

\begin{gathered} \tan \theta=\frac{DE}{EC} \\ \tan \theta=\frac{1.5}{2.5} \\ \tan \theta=0.6 \end{gathered}

Since angle of incidence will be equal to angle of reflection, \begin{gathered} \text{tan}Therefore, the height of cactus is 6 m.

6 0
8 months ago
Dailene has 30 CD's and buys two new ones each week. Renae has 18 CD's and buys 4 new ones each week. after now many weeks will
Naddika [18.5K]
6 Weeks is the awnser
3 0
2 years ago
PLease help me please
valkas [14]
Xy+24=x22 that is the answer hope it helps
7 0
3 years ago
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