Lets make k equal to Kate's age and j equal to Joey's age. If in 5 years Kate will be twice as old as Joe, you can write the equation k+5=2(j+5) and then simplify it to make it easier to work with.
k+5=2(j+5)
k+5=2j+10
k+5-2j=10
k-2j=5
since we know that right know Kate is 11 years older than Joey, you can write the equation k+j=11. Since you know have two equations with with the same variable, you can make a system of equations as fallows:
k-2j=5
k+j=11
Since you need to figure out how old Joey is, you need to somehow get k to cancel out. The easiest thing to do for this problem is to is multiply the top equation by -1 to get:
-k+2j=-5 (you have to add the bottom equation to the top equation)
k+j=11 (-k+k=0, 2j+j=3j, and -5+11=6)
Since k got canceled out, you are left with the equation 3j=6 which means j=2.
Therefore, Joey's current age is 2.
I hope this helps.
Step-by-step explanation:
Due to the time it took to solve this question, I had little time to type the answers fully
The answers are contained fully in the attachment I have uploaded.
A. H0: u1 = u2
H1: u1 not equal to u2
The t statistics was solved to be 3.03
The degree of freedom was solved to be 26
Given this information, this is a 3 tailed test, critical value at 5% = +-2.056
T stat > critical value
We therefore reject the null hypothesis at 5% and conclude they have different mean wear
The p value is calculated using excel and the result is 0.00544
We reject null at 5% since p value is less than 0.05
B. H0: u1 = u2
H1: u1>u2
Alpha = 0.05
Following a,
Test stat = 3.03
Df = 26
Critical value for 1 tailed test = 1.706
Test stat > 1.706
We reject H0 and conclude company 1 has higher mean wear.
We find p value for a right tailed distribution using excel
Tdist(3.03,26,1)
= 0.002722
We reject h0
C. Confidence interval
1.610 < u < 8.390
Answer:
wow thats mean
Step-by-step explanation:
Answer:
1.05
Step-by-step explanation:
Answer:
Step-by-step explanation:
OS ≅ OU, so we will set those 2 expressions equal to each other and solve for y:
6y = 42 so
y = 7
Same goes for OT and OV:
x + 5 = 23 so
x = 18 and
SU = 84
