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4 years ago

The two triangles above are similar.

Mathematics

1 answer:

melisa1 [442]4 years ago

4 0

Two similar angles is shown in the diagram below

Similar shapes have same angle and their side in proportion

Correct description is option c)

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Veronica brought her turtle out of its aquarium for 15 minutes for 7 days.How many total minutes did she bring the turtle out of

daser333 [38]

105 minutes
15*7 = 105

6 0

3 years ago

Someone please help I promise I will mark brainlest thank youuuu

aev [14]

Answer:

D. 0.7x+10.8

Step-by-step explanation:

I used desmos calculator and typed in all the equations and this is the only one that was close to the set of dots. I attached a screetshot so you can look for yourself. I hope this helps

5 0

3 years ago

Is the graph increasing, decreasing, or constant where 8 10 8 8- 4+ 2+ -2 -6 -8 -10

Lemur [1.5K]

Decreasing fore sure because the last four where decreasing so the going trend is going down ( decreasing )
Hope it helps

8 0

3 years ago

I need help with solving real world problems with the whole and perceng

BabaBlast [244]

divide the price of the olive oil by the volume of the olive oil to find the price per ounce. 5.88/25oz=0.2352 dollars/ounce. Then you have to multiply the volume of the bottle by .60 to find what 60% of the volume is.
0.60x25=15 ounces. since in the first two weeks she used 15 ounces which has a price of 0.2352 dollars/ounce you have to multiply 15 by 0.2352 which equals 3.528 dollars.

7 0

4 years ago

A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

pav-90 [236]

Answer:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

3 0

3 years ago