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3 years ago

Is a square a special parallelogram

Mathematics

1 answer:

Debora [2.8K]3 years ago

6 0

idk what a special parallelogram is but a square is most definitely a parallelogram :)

Answer:

a square is a quadrilateral but<em><u> is also a parallelogram</u></em>,rectangle and a rhombus

Step-by-step explanation:

a square is many things such as a parallelogram, a rectangle, and a rhombus.

it is a quadrilateral with all right angles and all equal sides

×║hope this helps║×

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aleksandrvk [35]

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2 years ago

What is (5,1) reflected on the y axis

asambeis [7]

Answer:

(-5 , 1)

Step-by-step explanation:

If you are reflecting over the x-axis, you are changing the sign of the y.

If you are reflecting over the y-axis, you are changing the sign of the x.

In this case, you have the point (5 , 1). You are reflecting over the y-axis, which means that you are flipping the sign of the x value.

(5 , 1) reflected over the y-axis is (-5 , 1)

(-5 , 1)

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2 years ago

Read 2 more answers

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masha68 [24]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

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2 years ago

Suppose the function y = 30,000(1.06)x models the annual profit for a small business x years after 2000. Find the profit at the

goldfiish [28.3K]

From 2000 to 2011, there are 11 years. From the given function, we can calculate the profit for a small business at the end of 2011 by substituting 11 to the x of the given equation.
y = (30,000)(1.06)(11)
y = 349,800
Thus, the profit at the end of 2011 is approximately $349,800.

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3 years ago