We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
Angle TVU = 1/2 (120 - 12) = 108/2 = 56°
Therefore, the correct answer is D.
Answer:
1. y=2x-3
2. y=4x-2
Step-by-step explanation:
The marked angles are opposite angles, and as such they have the same measure. So, we have
Subtract 2a and 11 from both sides to get
Divide both sides by 4 to get
Now that we know the value of a, we can compute the measure of the angles. We can also verify that the solution we found is correct by verifying that both expressions actually give the same result:
