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Nataly_w [17]
3 years ago
11

How many 20 degree angles does it take to make a full turn?

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0
There is 360* in a circle, so you would divide 360 by 20 to get 18. 
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Please help I don't understand!
podryga [215]

The statement <S and <H are equal in measure is False

<h3>How to determine the true statement?</h3>

The similarity statement is given as:

ΔRST is similar to ΔHGF

This means that:

  • Angles R and H are congruent
  • Angles S and G are congruent
  • Angles T and F are congruent

Hence, the statement <S and <H are equal in measure is False

Because S equals G and R equals H

Read more about similar triangles at:

brainly.com/question/14285697

#SPJ1

3 0
2 years ago
What set of reflections would carry parallelogram ABCD onto itself?
My name is Ann [436]
"y-axis, x-axis, y-axis, x-axis" is the set of reflections among the following choices given in the question that <span>would carry parallelogram ABCD onto itself. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that this is the answer that has helped you.</span>
5 0
3 years ago
Read 2 more answers
Find m&lt;_6 if m&lt;_8=120 degrees (show work if possible).
shepuryov [24]

Answer:

h

Step-by-step explanation:

i h you h we all h ya know

3 0
3 years ago
Help me asap (please please)
CaHeK987 [17]
Area of a circle = pi*r^2.

Here, A = 380.13 mi.  Unfortunately, "mi" is NOT a unit of area.

So I will assume that the problem should read   A = 380.13 sq. miles.
                                                                    380.12 mi^2
Thus,   380.13 mi^2 = 3.14*r^2, and r^2 = ------------------- 121.057 mi^2
                                                                           3.14

The radius is the sqrt of 121.057 mi^2:  11.00 miles.

The diam. is twice that, or d = 22.00 miles.



4 0
3 years ago
PLEASE HELPPPPP!!!!!!!!! (show work if you can)
Kryger [21]

Answer:

180x^4y^3z^2

Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

LCM(12,18,30)=180

Next, to find the least common multiple of each of the following terms, we need to take the absolute minimum we can of each term (x, y, and z). The largest term of x is x^4 in the first polynomial, so we'll take exactly that for our x term in the LCM, absolutely nothing more. Similarly, the largest term of y in any of the three polynomials is y^3 (also in the first polynomial) and the largest z term in any of the three polynomials is z^2 in the second polynomial. Thus, the LCM of all our polynomials is:

180\cdot x^4\cdot y^3\cdot z^2=\boxed{180x^4y^3z^2}

3 0
3 years ago
Read 2 more answers
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