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Musya8 [376]
3 years ago
11

What is the product of (2p + 7)(3p2 + 4p – 3)?

Mathematics
2 answers:
sveticcg [70]3 years ago
8 0

Answer:

6p^{3} +29p^{2} +22p-21

Step-by-step explanation:

This is a polynomial product where we have to apply distributive property and exponent properties (image is attached).

So, applying distributive property:

(2p + 7)(3p^{2}  + 4p-3)\\6p^{3}+8p^{2}-6p+21p^{2}+28p-21

Then, we reduce like terms:

6p^{3} +29p^{2} +22p-21

<h3><em>Therefore, the product is </em></h3>

6p^{3} +29p^{2} +22p-21

liraira [26]3 years ago
5 0
(2p + 7)(3p^2 + 4p - 3) = 2p(3p^2 + 4p - 3) + 7(3p^2 + 4p - 3) =
6p^3 + 8p^2 - 6p + 21p^2 + 28p - 21 =
6p^3 + 29p^2 + 22p - 21 <===
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Step-by-step explanation:

Given

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^{n}C_r => ^{n + 4}C_5

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^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

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^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

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Step-by-step explanation:

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