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grandymaker [24]
3 years ago
12

Which points are a solution to the graph

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

3,2

Step-by-step explanation:

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5.28 rounded to the nearest tenth
Bond [772]
5.28\to\boxed{5.30}
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3 years ago
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For making a scatter plot of the data set, which would be the best scale and interval for the axis that represents the amount of
Serga [27]

I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.

Because, you can't just have 1 to 4, as some of the numbers are less than 1.  Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.

For the second question:

I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.

So, the answers are: A) and D).

8 0
3 years ago
(x+5)(√ 1-x)<br> what is the product of this composite function?
Radda [10]

Answer:

x\sqrt{1-x}+5\sqrt{1-x}

Step-by-step explanation:

(x+5)(\sqrt{1-x} )\\\\=\left(\sqrt{1-x}\right)\left(x+5\right)\\\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\\\a=\left(\sqrt{1-x}\right),\:b=x,\:c=5\\\\=\left(\sqrt{1-x}\right)x+\left(\sqrt{1-x}\right)\times\:5\\\\=x\left(\sqrt{1-x}\right)+5\left(\sqrt{1-x}\right)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\=x\sqrt{1-x}+5\sqrt{1-x}

6 0
3 years ago
Suppose that you have $6,000 to invest. Which investment yields the greater return over a 10 year period: 7.44% compounded daily
Nikitich [7]
Hi
Here is you answer mate
But don’t forget to mark me the brainliest


Plug the applicable numbers into the compound interest formula and see which is more.
A = p(1+r/n)nt
A = future amount
p =principal investment
r = interest rate as a decimal
n = number times compounded per year
t = time in years

A = 5000(1+.0743/365)365(10)
= 5000(1.000203562)3650 = $10,510.38

A = 5000(1+.075/4)4(10)
= 5000(1.01875)40 = $10,511.75

As you can see these are practically equal, but the 7.5% quarterly is more.
3 0
3 years ago
Pwease help fast this is mah last question!
inessss [21]

Answer:

A  = 222 units^2

Step-by-step explanation:

To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB  (Call this point E).  Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units.  Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:

(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.

The area of this trapezoid is

A = (average vertical length)(width), which here is:

       (21 + 16) units

A  = --------------------- * (12 units),   which simplifies to:

                  2

A = (37/2 units)(12 units)  =  A  = 37*6 units  =  A  = 222 units^2

8 0
3 years ago
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