Which is a basic unit of a square molecule

valentina_108 [34]

It is the total mass of organisms in the given area

4 0

3 years ago

Use the following template strand of DNA and the coding table to determine the correct amino sequence and write this sequence be

REY [17]

DNA and RNA have the main difference in the presence of deoxyribose sugar in DNA and ribose sugar in RNA. One more is the presence of thymine in DNA while the presence of uracil in RNA.

<h3>What is the codon?</h3>

Codon is actually a three-letter code which is a sequence of three consecutive nucleotides in a DNA or RNA molecule which generally codes for a specific amino acid.

The DNA sequence given here is:

T A T A T C T A C G G T C C G G C A T C G A T T T C G

So the RNA sequence for this will be:

A U A U A G A U G C C A G G C C G U A G C U A A A G C.

So according to the table, the amino-acid sequence will be:

Isoleucine STOP Methionine Proline Glycine Arginine Serine STOP Serine.

Generally stop codon is responsible for the termination of protein synthesis.

Thus, this was the amino acid sequence for mRNA according to the given DNA sequence.

For more details regarding codon, visit:

brainly.com/question/22991780

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3 0

1 year ago

When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red

Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

RR- red
ww - white
Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

<u>From this cross the expected ratios are:</u>

1/4 RR (red)
2/4 Rw (pink)
1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3><u>Chi square test</u></h3>

$X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}$

<u>The observed frequencies were:</u>

34 Red
76 Pink
40 White

Total 150

<u>The expected frequencies for our null hypothesis are:</u>

1/4 x 150 = 37.5 Red
2/4 x 150 = 75 Pink
1/4 x 150 = 37.5 white

$X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}$

$X^2=0.5067$

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

8 0

2 years ago

What are yalls Zodiacs? I'm an Aries :3

xenn [34]

Answer:

scorpio

Explanation:

6 0

2 years ago

Read 2 more answers

Genetics experiments on the breeding of plants or animals are based on the laws of _____. segregation isolation genetics probabi

zzz [600]