Given:
Polynomial is
.
To find:
The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.
Solution:
The sum of given polynomial and the square of the binomial (x-8) is

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)

On combining like terms, we get


Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is
.
Answer:
<MBK because of the isosceles triangle theorem. If two sides of a triangle are congruent, it is isosceles, so the angles opposite them are also congruent.
Step-by-step explanation:
a. f(a) =5a+12
we have 1. a=6
Therefore, where ever we find a we'll substitute in 6
f(6) =5(6) +12
6f=30+12
6f=42
so therefore 1. a=6 will match c on the right
2. a=2
f(2) =5(2) +12
2f = 10+12
2f = 22
therefore 2. a=2 will match a on the right
3. a=4
f(4) =5(4) +12
4f=20+12
4f=32
therefore 3. a=4 will match d on the right
4. a=5
f(5) =5(5) +12
5f=25+12
5f=37
therefore 4. a=5 will match b on the right
1/4x - 5= y
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