Question

Please help ASAP!! WILL MARK BRAINLY!!

Answer 1

Answer:

$A=91^o$

$B=146^o$

$C=89^o$

$D=34^o$

Step-by-step explanation:

we know that

In an inscribed quadrilateral ABCD opposite angles are supplementary

so

$A+C=180^o$ ----> equation 1

$B+D=180^o$ ----> equation 2

step 1

Find the value of x

substitute the given values in equation 1

$(2x+3)^o+(2x+1)^o=180^o$

$4x=180-4\\4x=176\\x=44$

step 2

Find the measure of angle A,C and D

substitute the value of x

$A=(2(44)+3)=91^o$

$C=(2(44)+1)=89^o$

$D=(44-10)=34^o$

step 3

Find the measure of angle B

Remember the equation 2

$B+D=180^o$ ----> equation 2

substitute the value of D

$B+34^o=180^o$

$B=180^o-34^o=146^o$