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Mariana [72]
3 years ago
11

If the data analyst hypothesizes that grocery sales are lower on Sunday than on other days, the null hypothesis would likely sta

te that:
Mathematics
1 answer:
nlexa [21]3 years ago
7 0

Answer:

The answer is "Grocery sales are lower or no different on Sunday than on other days"

Step-by-step explanation:

Its null hypothesis does not always consider any discrepancy between both the comparable qualities throughout facts and figures. Furthermore, researchers recommend also have lower or even no opposite transactions for Sunday than with other days, because there is no connection between grocery sales and Saturdays and Sundays.

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14 – 8 + 5 – 2 + 6 – 11 = ? a. 4 b. 8 c. 20 d. 26
Otrada [13]

Answer:

A.4

Step-by-step explanation:

14-8=6

6+5=11

11-2=9

9+6=15

15-11=4

3 0
3 years ago
Read 2 more answers
On a scale drawing, which of the following has a scale of 1:6?
Alexandra [31]
The answer would be D, 2 cm represents 12 cm. 2/12=1/6
3 0
3 years ago
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How do you find the next three terms in the geometric sequence 9, -3, 1, , ... ?
levacccp [35]
Each term is being divided by -3, so the next three terms would be:

-1/3, 1/9, -1/27
7 0
3 years ago
10. MP Find the Error The rate of growth for a
Akimi4 [234]

Answer:

the error is how many days it will take for the plant to grow 3.6 centimeters they have 1.44 but the correct answer is 9 days.

Step-by-step explanation:

it will take the plant 9 days to grow 3.6 centimeters

4 0
2 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 421 gram setting. It is
Anastaziya [24]

Answer:

The p-value is approximately 0.0508

Step-by-step explanation:

The given parameters are;

The expected mass of banana chips bag filled by the machine, μ = 421 gams

The number of bags in the sample of bags filled by the machine, n = 26 bags

The mean mass of the bags in the sample, \overline x = 413 grams

The standard deviation of the mass in the bags, s = 24 grams

The level of significance, α = 0.02

The null hypothesis, H₀; μ = 421 grams

The alternative hypothesis, Hₐ; μ < 421 grams

The test statistic is given as follows;

t=\dfrac{\bar{x}-\mu }{\dfrac{s}{\sqrt{n}}}

We get;

t=\dfrac{413-421 }{\dfrac{24}{\sqrt{26}}} \approx -1.6996731712

The t-value = -1.6996731712

The degrees of freedom df = n - 1 = 26 - 1 = 25

From an online source, we get the critical-t =  2.166587

The p-value is obtained using an online source as p(t ≤  -1.6996731712) = 0.0508

From the p-value table, we get

0.05 < p < 0.1

3 0
2 years ago
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