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3 years ago

Write an equation passing through the point and perpendicular to the given line: (-3,5);y = 3/4x-4

Mathematics

1 answer:

balandron [24]3 years ago

7 0

Hey!

So the first thing we realize is that it says that the equation is perpendicular to the line, meaning that the slope of the line is the negative reciprocal of the slope of the line you are given. Since we are given the slope of this line as 3/4 we can take the negative reciprocal of this to get -(4/3).

Now that we have the slope and a point on the line you can plug those into the equation y = mx + b to find b. The slope of the line is m and the point contains the x and y values.

5 = -(4/3)(-3) + b

5 = 4 + b

1 = b

Since we have the y-intercept and the slope now we can plug that into the slope-intercept form equation to get the equation we need:

y = -(4/3)x + 1

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prisoha [69]

Answer:

B 9/10

Step-by-step explanation:

3/5 ÷2/3

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2 years ago

Rewrite 5-6 using the additive inverse and display the help this are the answers

NNADVOKAT [17]

Answer:

Additive inverse of (5-6) is (6-5),

------------------------------

So:

(5-6)+(6-5)=0

5-6+6-5=0

5-6=-6+5

-------------------------

Left <--- -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6 ---> Right

Move 5 places to the right of -6 and you should land on -1.

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2 years ago

The blue dot is at what value on the number line?

EastWind [94]

I think it’s 4 if the lines are going up by 2

4 0

2 years ago

Read 2 more answers

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

2 years ago

Four friends played minutes golf. Their scores were -3, -2, -1, and 2.

kramer

I had the same question just yesterday and the correct answer was 1.5
-3 +-2 = -5 + -1 = -6 - 2 = -4

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6 0

3 years ago