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frutty [35]
3 years ago
6

Company A charges a fee of $5 for a cab ride, plus a charge of $0.50 for each mile driven. Company B charges a fee of $10 for a

cab ride, plus a charge of $0.10 for each mile driven. For what number of miles driven will the cost of a cab ride be the same for both companies?
Mathematics
2 answers:
Blababa [14]3 years ago
8 0
<span>Each set of prices can be described by a linear function. In this case, Company A would be y = 5 + .5x, where y is the fare and x is the number of miles driven. Similarly, Company B would b y = 10 + .1x. The definition of intersection tells us that two lines interstect only at that point where their x and y coordinates are identical, which means, of course, that their y coordinates will be identical. So to find the point of intersection we can examine the point where the y coordinates are the same. Which is to say, where 5 + .5x = 10 + .1x. We can simplify this to .5x - .1x = 10 - 5, then .4x = 5, and finally, x = (5/.4) = 12.5. In other words, the fares will be equal when the miles driven is 12.5</span>
ivann1987 [24]3 years ago
3 0
Company A: 5$+0.5$*x miles
Company B: 10$+0.1$*x miles
5+0.5x=10+0.1x
0.5x-0.1x=10-5
0.4x=5, x=5/0.4
x=12.5miles.
For 12.5 miles driven, coast of a cab ride will be the same for both companies.
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X+y+z =4
cestrela7 [59]
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian : 
Akar-akar persamaan lama :  x1 dan x2
                                             
Akar-akar persamaan baru :  xA dan xB
                                             xA = 2x1 - 1
                                             xB = 2x2 - 1
                                             xA + xB  = (2x1 - 1) + (2x2 - 1)
                                                           = 2 (x1 + x2) - 2
                                                           = 2 () - 2
                                                           = 3 - 2
                                              xA + xB = 1
    
                                              xA . xB = (2x1 - 1) (2x2 - 1)
                                                          = 4 x1.x2 - 2(x1 + x2) + 1
                                                          = 4.(-) - 2() + 1
                                                          = -2 - 3 + 1
                                              xA . xB = -4
    
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
                                              x² - x - 4 = 0

</span></span>
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