See the attached figure which represent the rest of the question.
The rest of the question is the attached figure.
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As shown in the attached figure:
(1) ΔMNL is a right triangle at ∠MNL and ∠NML = 58°
∴ ∠L = 180° - (90°+58°) = 32°
(2) ΔQNL is a right triangle at ∠QNL and ∠QLN = 32°
∴ ∠Q = 180° - (90°+32°) = 58°
So, for both of ΔMNL and ΔQNL
1. ∠NLM = ∠ NLQ = 32°
2. ∠Q = ∠M = 58°
3. side NL = side NL
∴ ΔMNL is congruent to ΔQNL by AAS=======OR=======So, for both of ΔMNL and ΔQNL
1. ∠MNL = ∠QNL = 90°
2. side NL = side NL
3. ∠NLM = ∠ NLQ = 32°
∴ ΔMNL is congruent to ΔQNL by ASA=====================================
So, the correct answer is the first option
Yes, they are congruent by either ASA or AAS
Answer:
Range is (-8,00)
Step-by-step explanation:
Answer:
36.87
Step-by-step explanation:
Using tan inverse of 9 over 12
Answer: 3 equal sides a 3 vertices
Step-by-step explanation:
Answer:
y = x + 4
Step-by-step explanation:
The equation of the line is
y = mx + c
Step 1: find the slope
m = y2 - y1 / x2 - x1
Give points
( 2 , 6) ( -2 ,2)
x1 = 2
y1 = 6
x2 = -2
y2 = 2
m = 2 - 6 / -2 - 2
m = -4 / -4
m = 1
y = mx + c
y = 1x + c
y = x + c
Step 2: sub any of the two points given into the equation
( 2 , 6)
x = 2
y = 6
y = x + c
6 = 2 + c
6 - 2 = c
c = 4
Step 3: sub c into the equation
y = x + 4
The equation of the line is
y = x + 4