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Anni [7]
3 years ago
8

Reggie currently has a square rug in his living room. He is moving soon and has determined that for his new living room, he will

need a rug that has a width that is two feet shorter than his current rug and a length that is five feet longer than his current rug. Let x represents the side measure of Reggie's current rug, in feet. Determine the equation that represents the area, y, in square feet, of the rug needed for his new living room.
y = x2 + 3x - 10


y = x2 - 7x + 10


y = x2 - 3x - 10


y = x2 + 7x + 10
Mathematics
1 answer:
Tamiku [17]3 years ago
8 0
<h2>Greetings!</h2>

Answer:

y = x^{2} + 3x - 10

Step-by-step explanation:

Because Reggies rug is square, this means that there is a constant, x, that stays the same, because x * x = area of square

The new rug is 2 feet shorter than his current one, so this would be (x - 2). As the rug is also 5 feet longer than his current one, this would make it (x + 5).

<h3>To find the equation that represents the area, the area needs to be found using </h3><h3>Length x Width = Area</h3>

So simply plug the values into this equation:

(x - 2)(x + 5) = area

= (x * x) + (x * 5) + (-2 * x) + (-2 * 5)

= x^{2} + 5x + -2x + -10

A plus and a minus makes a negative:

x^{2} + 5x  -2x  -10

5x - 2x = 3x

<h3>So this would result in the end answer being:</h3>

x^{2} + 3x - 10


<h2>Hope this helps!</h2>
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3 years ago
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

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f(1) = 15(1)+4

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Common difference d = f(2)-f(1)

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f(2) = 34

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S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

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For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

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Sum of nth term of an AP = n/2{2a+(n-1)d}

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kicyunya [14]

Answer:

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If we assume values of <em>x </em>> 0 (non negative values for x), then the expression could be rewritten as follows:

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Domain: \\ {x | x \in R, x > 0}

8 0
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