Equation arrangement: 10 + [1/2]^4. 48
[1/2]^4 = 1/2 * 1/2 * 1/2 * 1/2 = 1/16
10 + [1/16] * 48
According to the law of BODMAS, we have to carry out multiplication operations before we carry out addition operations, therefore, we now have.
[1/16] * 48 = 3
Then, 10 +3 =13.
Thus, the final answer is 13.
The z-score corresponding to a cumulative area of 1 - 0.0122 = 0.9878 is 2.25.
Therefore the z-score corresponding to a cumulative area of 0.0122 is the negative of 2.25 = -2.25.
D is halfway between A and B
so the coordinates of D are (2,2)
E is halfway between A and C so the coordinates of E are (-1,1)
now you need to find the gradient/slope of DE and BC using the formula:

<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>
SUB IN COORDINATES OF D AND E

therefore the gradient of DE is 1/3.
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>
<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>
<em>
</em>
therefore the gradient of BC is -2/-6 which simplifies to 1/3.
<h3>
therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>
1.) Word form: two hundred thirty-six and seventy-seven thousandths
Expanded notation: 200
+ 30
+ 6 + 0.0 + 0.07 + 0.007
There are no underlines?
3.) tenth: 7.3 hundredth: 7.31 thousandth: 7.305 whole number: 7
4.) Estimate: 10,400
Answer is 10,417