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Nesterboy [21]
3 years ago
5

5.

Mathematics
1 answer:
hoa [83]3 years ago
6 0

Finding limits by direct substitution means simply means to evaluate the function at the desired value: in the first case, we have to evaluate f(x)=x^2-3 at x=0: we have

f(0)=0^2-3 = 0-3=-3

Similarly, in the second example, we have

f(x)=x^2+3x-1 \implies f(3) = 3^2+3\cdot 3-1 = 9+9-1 = 17

Going on, we have

f(x) = \dfrac{x^2-16}{x-4} = \dfrac{(x+4)(x-4)}{x-4} = x+4

And thus we have

f(4) = 4+4=8

Finally, we have

f(x) = \dfrac{x^2-2x}{x^4} = \dfrac{x(x-2)}{x^4} = \dfrac{x-2}{x^3}

So, we can't evaluate this function at 0.

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Answer:

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Step-by-step explanation:

We are given the following information in the question:

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Calculation the value from standard normal z table, we have,  p(z

\displaystyle\frac{x - 500}{100} = 0.358\\x = 535.8

P(x < 535.8) = 0.64

P_{64} = 535.8

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