2(2x − 1) > 6 or x + 3 ≤ −6
2(2x − 1) > 6
4x - 2 > 6
4x > 8
x > 2
or
x + 3 ≤ −6
x ≤ - 9
Solution: x ≤ - 9 or x > 2
(- ∞ , - 9] or (2 , + ∞)
Answer is the first one
(- ∞ , - 9] or (2 , + ∞)
Answer:
Width = 
Step-by-step explanation:
All we have to do is to use the method of changing the subject. First we know that length * width is equal to area.
Area = length * width
We have the area and the length but we don't have the width. So we substitute the values we have int the equation and make the width (w) the subject.
(c^2 - 4x - 12) = (x + 2) * w
(c^2 - 4x - 12) = w(x +2)
Divide both sides by (x+2) so w can stand alone.
w =
Answer:
12 11/35
Step-by-step explanation:
Given Data
First term= 15 3/5
To simple fracrion= 78/5
Second term= 3 2/7
To simple fracrion= 23/7
Hence the operation goes thus
= 78/5- 23/7
LCM = 35
=546-115/35
=431/35
=12 11/35
T<span>he product of -2x^3+x-5 and x^3-3x-4 would look like this before simplification:
-2x^6 + 6x^4 - 8x^3 + x^4 - 3x^2 - 4x - 5x^3 + 15 x^2 + 20
Now combine all the like terms. For example, 6x^4 + x^4 = 7x^4.
Write the product in the simplest possible form, which involves combining like terms and arranging them in descending order by power of x.
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