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slamgirl [31]
3 years ago
10

Convert 60% to a fraction in lowest terms

Mathematics
1 answer:
Doss [256]3 years ago
6 0

Answer:

3/5

Step-by-step explanation:

60% to a decimal is 0.6

0.6 to a fraction is 60/100

60/100 reduced is 3/5

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Jon wants to buy carpet to cover his whole living room, except for the tiled floor. The tiled floor
Firdavs [7]

Answer:

321/8 ft^2

Step-by-step explanation:

The whole area is 49/4 × 5 = 245/4 ft^2

The area of tiled floor is 13/2 × 13/4 = 169/8

245/4 - 169/8 we need to equalise the bottom of fraction to subtract so

2/2 × 245/4 = 490/8

490/8 - 169/8 = 321/8 ft^2

7 0
3 years ago
Write two equations that have one unique solution each
KonstantinChe [14]
10 plus 5x = 50(x=8)
62 times 2x = 128(x=31)
7 0
4 years ago
Given the midpoint and one endpoint. Find the other endpoint. B) Endpoint (-3,7), Midpoint (-1,-1)
astra-53 [7]

Answer:

Step-by-step explanation:

(x - 3)/2 = -1

x - 3 = -2

x = 1

(y + 7)/2 = -1

y + 7 = -2

y = -9

(1, -9) the other endpoint

4 0
4 years ago
Please any math experts help thanks you
timofeeve [1]

Answer:

\frac{p^2-25}{p^2-10p+25}

We can factorise the numerator with the difference of squares formula:x^2-y^2=(x+y)(x-y)

-----------------------------

\frac{p^2-5^2}{p^2-10p+25} =\frac{(p+5)(p-5)}{p^2-10p+25}

Now we can factorise the denominator:

\frac{(p+5)(p-5)}{p^2-10p+25} =\frac{(p+5)(p-5)}{(p-5)^2}

\frac{(p+5)(p-5)}{(p-5)^2} =\frac{(p+5)(p-5)}{(p-5)(p-5)}

Cancel out the common factor of (p-5):

\frac{(p+5)(p-5)}{(p-5)(p-5)} =\frac{(p+5)}{(p-5)}

7 0
3 years ago
Givin the area of a square is 225 square feet, what is the length of each side
Romashka [77]
The area of a square is calculated by squaring the length of the sides (multiplying by itself).  Therefore, in order to find the length, you must find the square root of 225. 

The square root of 225 is 15.  Therefore, you length of each side is 15 feet. 


p.s. I don't know how old you are, but I would recommend trying to memorise your square numbers up to 17^{2} .  I know I found that incredibly useful when it came to my exams last year (GCSEs)

7 0
4 years ago
Read 2 more answers
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