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Nata [24]
3 years ago
15

For each of the transactions in items 1 through 5, indicate the effects on the accounting equation elements.

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

Decrease I think.

Sorry if it is wrong.

Hope it helped :)

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3 years ago
What is the solution for 2y=x+2<br> x-3y=-5
Mars2501 [29]

Answer:

x = 4

y = 3

Step-by-step explanation:

<u>Given </u><u>equations </u><u>:</u><u>-</u>

  • 2y = x + 2
  • x - 3y = -5

<u>Second</u><u> </u><u>equation</u><u> </u><u>can </u><u>be</u><u> written</u><u> as</u><u> </u><u>,</u><u> </u>

  • x - 3y = -5
  • -3y = -x - 5

<u>Adding</u><u> </u><u>them </u><u>:</u><u>-</u><u> </u>

  • -3y + 2y = 2 -5
  • -y = -3
  • y = 3

<u>Put </u><u>this </u><u>in </u><u>(</u><u>ii)</u><u> </u><u>:</u><u>-</u><u> </u>

  • x = 3y - 5
  • x = 3*3 - 5
  • x = 9 -5
  • X = 4
8 0
3 years ago
Read 2 more answers
Please help me I need this in like 10min
Gre4nikov [31]

Answer:

1. congreunt; reflection

2. not congruent

3. congruent; rotation & translation

4. 64 cm

5. 62 degrees

Step-by-step explanation:

7 0
3 years ago
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Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
What is the slope of the line represented by the equation 4x 5y = 10?
Tresset [83]
Im not sure how to do it because you don't have a plus or minus sign. add that and then i will show you.
8 0
3 years ago
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