Answer:
Step-by-step explanation:
just times everything 3.5 as 42/12=3.5
490g margarine
420g sugar
350ml syrup
840g oats
175g raisins
Answer:
Step-by-step explanation:
Let's use the addition/elimination method to solve this. If we multiply the first equation through by -1 we can eliminate the x terms. Doing that gives us:
-x + 3y = 3
x + 3y = 9
The x's subtract each other away leaving us with
6y = 12 so
y = 2.
Now we will plug in 2 for y in either of the original equations to solve for x:
x + 3(2) = 9 and
x + 6 = 9 so
x = 3
The coordinate for the solution is (3, 2) or x = 3, y = 2
The second choice down is the one you want.
<em>Since we are given with the three sides of the triangle and asked to determine the angle, we can use the cosine law.</em>
<em> b² = a² + c² - 2ac(cosB)</em>
<em>Substituting the known values,</em>
<em> (1.8)² = (2.4)² + (1.6)² - 2(2.4)(1.6)(cosB)</em>
<em>The value of B from the equation is 48.6°. </em>
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792
