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2 years ago

11

Help me with this please

1 answer:

Bess [88]2 years ago

3 0

Answer:

A

Step-by-step explanation:

Brainliest PLEASE

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7. 25 and 8. 18. I think it is. I hoped that is was right.

Step-by-step explanation:

150/6=25. 90/5=18.

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3 years ago

Shau-uen solve the equation 18.5w+6.5w-2.8w=149.1 Her work is shown below

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A student scores 83,90, and 85 on the first three science test this year

Pepsi [2]

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Step-by-step explanation:

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3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

Monic and Rachel purchased a tv for $378. Monica paid $36 less then Rachel. How many did each person pay for the tv? Solve using

topjm [15]

Answer:

Monica paid $171 while Rachel paid $207

Step-by-step explanation:

We are told that Monic and Rachel purchased a tv for $378.

Let the amount spent by Monica be X and the amount spent by Rachel be Y.

Thus;

x + y = 378 - - - - (eq 1)

We are told that Monica paid $36 less then Rachel. Thus;

y = x + 36

Or y - x = 36 - - - (eq 2)

Add eq 1 & eq 2 together to give;

2y = 378 + 36

2y = 414

y = 414/2

y = $207

Put 207 for x in eq 1 to get;

x + 207 = 378

x = 378 - 207

x = $171

Thus;

Monica paid $171 while Rachel paid $207

8 0

2 years ago