Answer: The chemical reaction in this example is Called hydrolysis in the presence of Lactase
Here is a word equation for the hydrolysis of lactose:
lactose + water → galactose + glucose
Explanation: The equation is called <hydro> + <lysis) of these terms refer to water and splitting respectively. So hydrolysis means splitting with water. Enzymes pull out a monomer by examining where the monomers are connected, and placing a water molecule in between them, resulting in the breakage of the bond between the monomers. Here are two picture to represent it.
<span>These are organelles.
An organelle is the part of a cell that has a specific purpose in a cell. The structure of the cell is made up of many different organelles. The chloroplast consists of chlorophyll and the cell wall. The chloroplast helps with photosynthesis. Animal cells do not contain chlorophyll as they do not need photosynthesis to generate energy. A plant is unable to turn the sun's rays into a food source without photosynthesis.
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Water and nutrients make glucose
- - <span>B) ribosome
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The ribosome contains enzymes that are associated with protein synthesis.
Answer:
FfPp
Explanation:
If we take the two traits to be separate alleles, we can make flowers F (F is dominant; f is recessive) and pollen as P (P is dominant; p is recessive). So a pea plant with white flowers (recessive) and long pollen (dominant) will have the genotype ffPp or ffPP (because one dominant allele will express a dominant phenotype).
For this question, we will assume that the wild type (red flowers and long pollen) is homozygous, meaning it contains two dominant alleles.
If the wild type (FFPP) is crossed with the plant with white flowers and short pollen (ffpp), we can make a table illustrating the crosses. However, because there is only one possible gamete that each parent can form (FP and fp), we can assume that the F1 progeny will have identical genotypes, which can be expressed as FfPp (because combining the gamete from the wild type and the other parent can only give one phenotype).