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aliina [53]
4 years ago
13

What does the term edit warring mean?

Computers and Technology
1 answer:
iren2701 [21]4 years ago
8 0

Edit war is a term that is used in Wiki pages. This term describes an occurrence where (A) two or more editors constantly change the same article due to conflicting opinions.

Editors are heavily discouraged to do this – disagreements are supposed to be resolved via discussions, not through a succession of editing the same wiki page.

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Which of the following is the 1's complement of 10?
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Flip 10 and you get 01 then you add 1 to it:
1
01
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So, C. 11
6 0
3 years ago
Read 2 more answers
a) (20 points) Define the method inDogish recursively such that it returns true if the word is in dog-ish and false if it is not
tia_tia [17]

Answer:

/ Main.java

class Main {

     public static void main(String[] args) {

           //System.out.println(inDogish("aplderogad"));

           //System.out.println(inXish("aplderogad", "dog"));

     }

     // returns true if the word is in dog-ish

     // returns false if word is not in dog-ish

     public static boolean inDogish(String word) {

           /**

           * Note: we can use the inXish() method to complete this method in a

           * single line if you want. just write 'return inXish(word,"dog");' and

           * you are done.

           */

           // if word is null or empty, returning false

           if (word == null || word.length() == 0) {

                 return false;

           }

           // converting word to lower case

           word = word.toLowerCase();

           // if 'd' does not exist on the word, returning false

           if (!dogishHelper(word, 'd')) {

                 return false;

           }

           // removing the characters upto first 'd' in word

           word = word.substring(word.indexOf('d') + 1);

           // if 'o' does not exist on the word, returning false

           if (!dogishHelper(word, 'o')) {

                 return false;

           }

           // removing the characters upto first 'o' in word

           word = word.substring(word.indexOf('o') + 1);

           // if 'g' does not exist on the word, returning false, otherwise

           // returning true

           if (!dogishHelper(word, 'g')) {

                 return false;

           } else {

                 return true;

           }

     }

     // necessary to implement inDogish recursively.

     // returns true if letter is in word, else not.

     public static boolean dogishHelper(String word, char letter) {

           // if word is empty, returning -1

           if (word == null || word.length() == 0) {

                 return false;

           }

           // if first character in word is letter, returning 0

           if (word.charAt(0) == letter) {

                 return true;

           }

           return dogishHelper(word.substring(1), letter);

     }

     // the best thing about the above helper method is that we can use it in

     // inXish method also

     // a generalized version of the inDogish method

     public static boolean inXish(String word, String x) {

           // if x is empty, returning true (base case, which means all the letters

           // in x are in word in that order)

           if (x.length() == 0) {

                 return true;

           }

           // getting first character of x

           char first = x.charAt(0);

           // if first character does not exist on the word, returning false

           if (!dogishHelper(word, first)) {

                 return false;

           }

           // calling and returning inXish recursively, passing the word after

           // removing characters upto first occurrance of char first, and x after

           // removing first character from it

           return inXish(word.substring(word.indexOf(first) + 1), x.substring(1));

     }

}

Explanation:

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Mike needs to export some animation videos from his smartphone to an online platform. Which common file format can he use for th
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The answer would be b
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Write an if/else statement that adds 1 to the variable minors if the variable age is less than 18, adds 1 to the variable adults
BARSIC [14]

Answer:

if (age < 18)  // check condition of variable age is less than 18

minors=minors+`1;

else if (age >=18 && age <=64)  //check condition of variable age between 18 to 64

adults=adults+1;

else  // check condition of variable age more than 65

seniors=seniors+1;

Explanation:

Here we checks the condition if the  variable age is less than 18 then it increment the value of variable 'minors' by 1  i.e, minors=minors+`1; .

if variable age is 18 through 64 then it increment the value of variable adults by 1 i.e,'adults'=adults+1;  otherwise increment the value of variable 'seniors ' by 1  i.e seniors=seniors+1;

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4 years ago
What can cause a Lenovo computer to be very slow right after after turning it on?
emmasim [6.3K]

Explanation:

There are many quick fixes that even novice computer users can make to ... When all else fails, you can resort to reinstalling Windows.

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