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aliina [53]
4 years ago
13

What does the term edit warring mean?

Computers and Technology
1 answer:
iren2701 [21]4 years ago
8 0

Edit war is a term that is used in Wiki pages. This term describes an occurrence where (A) two or more editors constantly change the same article due to conflicting opinions.

Editors are heavily discouraged to do this – disagreements are supposed to be resolved via discussions, not through a succession of editing the same wiki page.

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Given the function definition below, what is the effect of thecall:
Romashka-Z-Leto [24]

Answer:

Hi!

The correct answer is E.

Explanation:

void change(int ar[], int low, inthigh)  {  

 int temp;

 if(low< high)  {  <em>// here ask if the positions low and high of the array are the same.</em>

  temp= ar[low];  <em>// first, saves the element on ar[low] in temp.</em>

  ar[low]= ar[high];  <em>// second, the element on ar[high] in ar[low]. First switch.</em>

  ar[high]= temp;  <em>// third, saves the element on temp in ar[high]. Complete switch.</em>

  change(ar,low + 1, high - 1);  <em>// Recursive call, adding one position to low, and subtracting one position to high. </em><em>Important: </em><em>When low and high have the same value, the recursive call will finish.</em>

}

}

Result: Switch the lower half of elements in the array with the upper half.

8 0
3 years ago
Read 2 more answers
Why is there more content on youtube in 4k then there is on cable, satellite, and digital tv combined?
barxatty [35]
So many more people all around the world have easy access to youtube
3 0
3 years ago
Read 2 more answers
printLarger is a method that accepts two int arguments and returns no value. Two int variables, sales1 and sales2, have already
gizmo_the_mogwai [7]

Answer:

<em>public static void printLarger(double sales1, double sales2){</em>

<em>        if (sales1>sales2){</em>

<em>            System.out.println(sales1+" is larger");</em>

<em>        }</em>

<em>        else {</em>

<em>            System.out.println(sales2+" is larger");</em>

<em>        }</em>

<em>    }</em>

<em>A complete code calling the printLarger method is given below</em>

Explanation:

<em>public class Larger{</em>

<em>    public static void main(String[] args) {</em>

<em>        int sales1 = 100;</em>

<em>        int sales2 = 120;</em>

<em>        printLarger(sales1,sales2);</em>

<em>    }</em>

<em>public static void printLarger(int sales1, int sales2){</em>

<em>        if (sales1>sales2){</em>

<em>            System.out.println(sales1+" is larger");</em>

<em>        }</em>

<em>        else {</em>

<em>            System.out.println(sales2+" is larger");</em>

<em>        }</em>

<em>    }</em>

}

6 0
3 years ago
A ____ is a program that lets computer users create and access a collection of organized data.
ruslelena [56]
Database management system
5 0
3 years ago
Create a program that includes a function called toUpperCamelCase that takes a string (consisting of lowercase words and spaces)
astraxan [27]

Answer:

#include<iostream>

using namespace std;

//method to remove the spaces and convert the first character of each word to uppercase

string

toUpperCameICase (string str)

{

string result;

int i, j;

//loop will continue till end

for (i = 0, j = 0; str[i] != '\0'; i++)

{

 if (i == 0)       //condition to convert the first character into uppercase

  {

  if (str[i] >= 'a' && str[i] <= 'z')   //condition for lowercase

  str[i] = str[i] - 32;   //convert to uppercase

  }

if (str[i] == ' ')   //condition for space

  if (str[i + 1] >= 'a' && str[i + 1] <= 'z')   //condition to check whether the character after space is lowercase or not

  str[i + 1] = str[i + 1] - 32;   //convert into uppercase

if (str[i] != ' ')   //condition for non sppace character

  {

  result = result + str[i];   //append the non space character into string

  }

}

//return the string

return (result);

}

//driver program

int main ()

{

string str;

char ch;

//infinite loop

while (1)

{

fflush (stdin);

//cout<< endl;

getline (cin, str);   //read the string

//print the result

//cout<< endl << "Q";

// cin >> ch; //ask user to continue or not

ch = str[0];

if (ch == 'q' || ch == 'Q')   //is user will enter Q then terminatethe loop

  break;

cout << toUpperCameICase (str);

cout << endl;

}

return 0;

}

8 0
3 years ago
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