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3 years ago

What is the solution to -3x-42>3

1 answer:

3 0

-3x-42>3
Add 42 to each side:
-3x>45
Divide by -3 on each side, but since you are diving by a negative, you have to flip the sign of the inequality:
x<45/-3

x<-15

Hope this helps :)

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let f(x)= p+ 8/x-q. the line x=4 is a vertical asymptote to the graph of f. what is the value of q and p, if the y intercept is

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Answer:

The value of q and p is 4 and -24 respectively.

Step-by-step explanation:

Being $f(x)=\frac{p+8}{x-q}$ , the line x=4 is a vertical asymptote to the graph of f(x). The line r is an asymptote of a function if the graph of the function is infinitely close to the line r. That is, an asymptote is a line to which a function approaches indefinitely, without ever touching it.

Being a rational function that which can be expressed as the quotient of two polynomials, a vertical asymptote occurs when the denominator is 0, that is, where the function is not defined. In this case:

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Solving:

x= q

Being the line x=4 the vertical asymptote, then

4=q

Then the function f (x) is:

$f(x)=y=\frac{p+8}{x-4}$

The y intercept is (0,4). This is, x= 0 and y=4. Replacing:

$4=\frac{p+8}{0-4}$

Solving:

$4=\frac{p+8}{-4}$

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$\displaystyle \bf \\
x_1+x_2=6\\\\
x_1\cdot x_2=15\\\\
\Longrightarrow~~x^2-6x+15=0\\\\
x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-60}}{2}=\\\\
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x_1=\boxed{3-i\sqrt{6}}\\\\
x_2=\boxed{3+i\sqrt{6}}\\\\
\texttt{Verify:}\\\\
x_1+x_2=3-\underline{i\sqrt{6}}+3+\underline{i\sqrt{6}}=3+3=6~~correct\\\\
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