Answer: The correct answer to the question is option WHEN GLUCOSE LEVELS ARE LOW AND LACTOSE IS PRESENT.
Explanation: To start with,Lac operon can be simply defined as a part of the DNA that is under the part of the DNA is manipulated and controlled by the same promoter,they can be found in some prokaryotic cells giving room for regulation over excess synthesis of protein.so simply put,these specific segment of the DNA binds with the segment of the polymerase of RNA so that transcription of the mRNA from the operon genes will be achieved.
Lac operon is also known as lactose operon, it is seen in some enteric bacteria like e.coli where they play a crucial role in coding of genes for those proteins that function in moving lactose into the cystocel and digesting it to form glucose that is used for energy generation. These lac operon are are most active when glucose levels are low and lactose is present,with the low level of glucose, the lac operon can be transcribed to a high level,this is to ascertain that the bacteria only gets to activate the lac operon and can only make use of it,that is using lactose when all the preferred energy source from glucose has been exhausted.
C. At a pH of 8, the enzyme starts to denature and changes shape.
I, seems to be the answer, because its not a sexual reproduction, (this occurs in cells, its not sexual reproduction, you would need the egg and sperm.
The answer to the above question is in a hot spring.
<h3>What is a habitat?</h3>
The term "habitat" in ecology refers to a region's collection of biotic, physical, and resource elements that are present to support a specific species' ability to survive and reproduce. It is possible to think of a species' habitat as the outward representation of its biological niche. As a result, "habitat" refers to a particular species, which is fundamentally distinct from ideas like "environment" or "vegetation assemblages," for which the term "habitat-type" is more applicable.
To learn more about habitat with the help of given link:
brainly.com/question/728057
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Answer:
The correct option is 3. "At pH 6.5 the enyzme is 50% active"
Explanation:
For the titratable group to be protonated and cause the enzyme to be in the active state, it needs to have gained a hydrogen cation (H+). In order for that to happen, there must be enough hydrogen cations in the environment of the enzyme, and hence, an acidic pH is required in this case.
