It would collapse or implode
        
             
        
        
        
Answer:
D. Cytokines
Explanation:
I would utilize Cytokines to recruit more leukocytes to the battle.
Cytokines are important chemical messengers that act via receptors in the immune system of the body. They are a group of proteins made by various immune cells. Immune cells communicate through Cytokines in regulating immune response
 
        
             
        
        
        
The classes of chordata which are warm-blooded are birds and mammals.
Explanation:
Warm-blooded animals are those which can maintain their body temperature at a constant.  
These classes of chordates balance their internal body temperature with that of the outer environment. When the outer environment is cold, they increase their internal temperature by producing more heat; and when it is hot outside they reduce their internal temperature by cooling themselves.  
The food consumed by a warm-blooded animal fuels to maintain a constant body temperature and hence they require more food.  
Warm blooded animals cool themselves with the help of sweat glands.  
The skin and other parts like fur in birds help to keep the animals warm during winter. Birds also shed their fur in hot season to keep them light. Birds migrate to warm regions during winter.
These animals have high stamina and energy to survive environmental changes. They maintain their temperature through endothermy, homeothermy or tachymetabolism.
Whale living in water is the fish which is also warm blooded because it is a mammal. 
 
        
             
        
        
        
Answer:
a. 8.1 milligrams
b. 40.07 hours
c. 8.859 milligrams
Explanation:
If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by

Where A(t) = amount of Valium remaining in the blood after t hours
t = time or duration after the drug is taken
a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours


                 = 10×0.81253
                 = 8.1 milligrams
b. In this part we have to calculate the time when A(t) = 5 milligrams


0.5 = 
Now we take natural log on both the sides of the equation.
ln(0.5) = ln(
-0.69314 = -0.0173t
t = 
t = 40.0658 
  ≈ 40.07 hours
c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.


               = 10×0.8859
               = 8.859 milligrams