If an is 18 and as is half its length it would be 9, AD = 9
The correct answer is C.
You can tell this by factoring the equation to get the zeros. To start, pull out the greatest common factor.
f(x) = x^4 + x^3 - 2x^2
Since each term has at least x^2, we can factor it out.
f(x) = x^2(x^2 + x - 2)
Now we can factor the inside by looking for factors of the constant, which is 2, that add up to the coefficient of x. 2 and -1 both add up to 1 and multiply to -2. So, we place these two numbers in parenthesis with an x.
f(x) = x^2(x + 2)(x - 1)
Now we can also separate the x^2 into 2 x's.
f(x) = (x)(x)(x + 2)(x - 1)
To find the zeros, we need to set them all equal to 0
x = 0
x = 0
x + 2 = 0
x = -2
x - 1 = 0
x = 1
Since there are two 0's, we know the graph just touches there. Since there are 1 of the other two numbers, we know that it crosses there.
Answer:
None
Step-by-step explanation:
The center of the ellipse is at (2, 4)
The length of the x axis is a= (8-2) =6
The length of the y axis is b=(16-4) = 12
The formula for an ellipse is
(x-h) ^2 (y-k)^2
----------- + -------------- = 1^2
a^2 b^2
where (h,k) is the center
and a and b are the lengths of the major and minor axes
(x-2) ^2 (y-4)^2
----------- + -------------- = 1
6^2 12^2
none of your choices have b>a and for the ellipse to be vertical b>a
I believe the answer is 25% because 6/24 is 1/4 and 1/4= 25%
