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Amanda [17]
3 years ago
15

What type of transformation is performed when the pre-image is "flipped" over a line? translation

Mathematics
2 answers:
vivado [14]3 years ago
8 0
Reflection is when the pre-image is flipped over a line.
Oksi-84 [34.3K]3 years ago
8 0
Im not 100% sure but i think the answer is reflection. Hope this helps you! Sorry if its wrong.
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Use the graph to write a linear function that relates y to x<br> NO LINKS THANK YOU
kipiarov [429]

Answer:

I uploaded a file hosting link for your question.

See below for more details.

Step-by-step explanation:

m=\frac{change(y)}{change(x)}

=\frac{10-2}{6-0}

=\frac{8}{6}

m=\frac{4}{3}

6 0
3 years ago
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Which theme does the previous quote illustrate? Question 3 options: Often a huge gap exists between perception and reality. Love
timurjin [86]

The information is incomplete hence the general answer. Please note that the question is about the Theme.

<h3>What is a Theme in Literature?</h3>

In works of literature, a theme is a key idea or principle that the writer explores in the text.

In order to identify the theme, you have to pay close attention to the characters, the setting, the plot, what the dialogue is (that is what are the characters talking about?) etc.

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7 0
3 years ago
The product of -3 and -7 is positive.<br><br><br> True or False
bagirrra123 [75]

Answer:

false

Step-by-step explanation:

cuz how could negative be positive

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3 years ago
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There are five students of different ages. Their median age is 13 years A) what are two possibilities for the ages of the three
Levart [38]
A) the median is the middle measurement. Their ages could be 13, 14 and 15.
B) 2 students must be younger than 13
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:) Have a nice day and maybe consider grading this answer brainliest? <3
6 0
3 years ago
FAST!! Evaluate tan60/cos45<br> √6<br> √3/2<br> √2/3<br> 1√6
evablogger [386]

Answer:

\frac{\tan 60\degree}{\cos45 \degree}= \sqrt{6}

Step-by-step explanation:

We want to evaluate

\frac{\tan 60\degree}{\cos45 \degree}

We use special angles or the unit circle to obtain;

\frac{\tan 60\degree}{\cos45 \degree}=\frac{\sqrt{3}}{\frac{\sqrt{2}}{2}}

This implies that;

\frac{\tan 60\degree}{\cos45 \degree}=\sqrt{3}\div \frac{\sqrt{2}}{2}

\frac{\tan 60\degree}{\cos45 \degree}=\sqrt{3}\times \sqrt{2}

\frac{\tan 60\degree}{\cos45 \degree}= \sqrt{6}

4 0
3 years ago
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