Correct Ans:Option A. 0.0100
Solution:We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.
First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.
Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
[deleted due to wrong answer]
(0,0)(1/3,7/3)
slope = (7/3 - 0) / (1/3 - 0) = (7/3) / (1/3) = 7/3 * 3 = 21/3 = 7 <==
Answer:
40 + x = y
Just use the variables given to make an equation.
9514 1404 393
Answer:
no solution
Step-by-step explanation:
The equations describe parallel lines. There are no values of x and y that will satisfy both equations.
In standard form, the two equations are ...
3x +7y = 21
3x +7y = -42 . . . . . with positive leading coefficient
If (x, y) values satisfy the first equation, they cannot satisfy the second equation, and vice versa.