Ok so there are 52 cards in a deck if you take all the cards that have the number 6 which is only 4 cards so 52-4 = 48 cards without any 6 so the ratio is 48/52
chances.
If you're trying to take any card that is greater than 6 its a little more complex there is T,2,3,4,5,6,7,8,9,10,B,Q,K so you have to tack away 6,7,8,9,10,B,Q,K from 4 rows so 8 x 4 =32 cards 52-32= 20 so the probability of not having any cards greater than 6 is 20/52
Answer:
p > 10
Step-by-step explanation:
Given
- 6(p - 8) < - 12
Divide both sides by - 6, reversing the symbol as a result of dividing by a negative quantity.
p - 8 > 2 ( add 8 to both sides )
p > 10
Answer:
The $1 belongs to the cash box
Step-by-step explanation:
Given
See attachment for complete question
Required
Determine if the $1 belongs to the cash box or not
Represent singles with s and couples with c.
From the attachment, we have:
--- total attendance
--- ticket sold
Solve for s and c.
Make s the subject in (1)
Substitute 47 - c for s in (2)
Open bracket
This means that the total individual which makes up the couples are 35. This is not possible because couples are in 2's and the total should be an even number.
<em>So, we can conclude that the $1 belongs to the cash box</em>
Answer:
11/12
Step-by-step explanation:
(1 1/10)/(1 1/5) = 1.1/1.2 = 11/12
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You can also work this using improper fractions:
(1 1/10)/(1 1/5) = (11/10)/(6/5) = 11/10×5/6 = (11×5)/(6×10)
= (11×5)/(6×2×5) = 11/(6×2) = 11/12
Answer:
6x - 4
Step-by-step explanation:
f(x) + g(x)
= 4x + 8 + 2x - 12 ← collect liketerms
= 6x - 4
