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2 years ago

15

Simplify each expression. Write your answers in exponential notation.

1 answer:

GenaCL600 [577]2 years ago

3 0

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad
a^n\implies \cfrac{1}{a^{-n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{36b^3}{9a^5} \right)^3\implies \left( \cfrac{4b^3}{a^5} \right)^3\implies \stackrel{\textit{distributing the exponent}}{\left(\cfrac{4^3b^{3\cdot 3}}{a^{5\cdot 3}}\right)}\implies \cfrac{64b^9}{a^{15}}$

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Thepotemich [5.8K]

Answer:

The value is $\left 35 } \atop }} \right. P_3 = 39270$

Step-by-step explanation:

From the question we are told that

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$\left n } \atop }} \right. P_r = \frac{n!}{(n - r) !}$

$\left 35 } \atop }} \right. P_3 = \frac{35! }{(35 - 3) !}$

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Tpy6a [65]

Answer:

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Step-by-step explanation:

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In this question:

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See below.

Step-by-step explanation:

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Read 2 more answers

What is the value of x for 7x - 12 y = 180 / 7x = 84

katrin2010 [14]

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therefore x is equal to 12. Then

1) take that 12 you got in equation 2 and substitute in equation 1 which is:

7x-12y=180

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84 -12y=180

-12y=180-84

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-y=8 (×-1) both sides

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