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Volgvan
3 years ago
11

What is the smallest integer greater than 237 for which each digit of the integer is a prime number?

Mathematics
2 answers:
Nesterboy [21]3 years ago
6 0
I think the answer is 252 because it is the next possible number with all its digits being a prime number
artcher [175]3 years ago
6 0

Answer:

252  

Step-by-step explanation:

Here's how I would argue.

Let the three digits be a, b, and c,

Then the number is abc.

Assume a = 2 and b= 3.  

Then c cannot be 8, 9, or 0, because they are not prime numbers.

b cannot equal 4 (not prime), so  

Assume that b = 5 (prime).

a cannot be 0 or 1 (not prime), but it can equal 2 (prime).

abc = 252

Thus, 252 is the smallest integer greater than 237 for which each digit is a prime.

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What is the value of x in the equation 6(x + 1) – 5x = 8 + 2(x - 1)?<br> OIT MT
Alexandra [31]

Answer:

x=0

Step-by-step explanation:

To solve, we need to get all the variables on one side of the equation, and all the numbers on the other

6(x + 1) – 5x = 8 + 2(x - 1)

First, distribute the 6 on the left

6*x+6*1 -5x=8 +2(x-1)

6x+6-5x=8+2(x=1)

Combine like terms on the left

(6x-5x)+6=8+2(x-1)

x+6=8+2(x-1)

Distribute the 2 on the right

x+6=8+2*x+2*-1

x+6=8+2x-2

Combine like terms on the right

x+6=2x+(8-2)

x+6=2x+6

Subtract x from both sides

6=x+6

Subtract 6 from both sides

x=0

Hope this helps! :)

3 0
3 years ago
Make r the subject of the formula <br><br><img src="https://tex.z-dn.net/?f=v%20%3D%20mg%20%5Csqrt%7B%281%20-%20r%20%7B%7D%5E%7B
serg [7]

\huge\underline{\purple{\bold{your \: answer \: is \: in \: attachment}}}

4 0
2 years ago
Solve the System by Graphing:
Marat540 [252]

Answer:

  • B) One solution
  • The solution is  (2, -2)
  • The graph is below.

=========================================================

Explanation:

I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.

Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.

--------

To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,

y = (-3/2)x+1

y = (-3/2)*0+1

y = 1

The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.

7 0
2 years ago
can someone write a subtraction problem that has a mixed numbers and requires a number remaining. PLEASE AND THANK U
Rufina [12.5K]
1/2 -3/6 is equal to 0 because 1/2 is equal to 1/2
4 0
3 years ago
(( I will give 25 points and brainy from right answers (Please answer all!!) )
sleet_krkn [62]
1. C. Concave pentagon

2. A. 1620°

b/c (11 - 2) × 180 = 1620

3. B. 165°

b/c (24 - 2) × 180 ÷ 24 = 165

4. A. 160°

b/c (18 - 2) × 180 ÷ 18 = 160
6 0
3 years ago
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