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4 years ago

What is the smallest integer greater than 237 for which each digit of the integer is a prime number?

Mathematics

2 answers:

Nesterboy [21]4 years ago

6 0

I think the answer is 252 because it is the next possible number with all its digits being a prime number

artcher [175]4 years ago

6 0

Answer:

252

Step-by-step explanation:

Here's how I would argue.

Let the three digits be a, b, and c,

Then the number is abc.

Assume a = 2 and b= 3.

Then c cannot be 8, 9, or 0, because they are not prime numbers.

b cannot equal 4 (not prime), so

Assume that b = 5 (prime).

a cannot be 0 or 1 (not prime), but it can equal 2 (prime).

abc = 252

Thus, 252 is the smallest integer greater than 237 for which each digit is a prime.

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The answer is C. $256\pi$ $in^2$ .

Step-by-step explanation:

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3 years ago

What is the product of 3 square root 7 and 17 square root 14 in simplest radical form

Aleks [24]

$3 \sqrt{7} \times 17 \sqrt{14}$

This is the problem that we need to solve. The best way to get about it is to first:

Multiply the constant numbers (3 and 17). 3×17 is 51.
Next multiply the radicals.
$\sqrt{7} \times \sqrt{14} = \sqrt{7 \times 14} = \sqrt{108}$
Simplify the squareroot of 108 since it is 49 times 2. It would be equal to 7 squareroots of 2.
Our final answer would be:
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51 x 7 is 357, so the answer above is right.

The skills needed are multiplication, mulitplication of radicals, and simplifying radicals, so if you want to review anything use these as reference.

Hope you understood and have a nice day!!

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