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3 years ago

What is the value of x in the following equation? 2 (x - 4) + 15 = 21

Mathematics

1 answer:

viktelen [127]3 years ago

5 0

The answer would be x=7.

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Shane wants to buy a 3D television set. He has saved some money and is able to pay $600 as a down payment and is making monthly

Harman [31]

Answer:

the equation is

p = 600 + 150x

x is month

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3 years ago

In the right triangle shown, mZA = 45° and AB = 12.<br> B<br> 12<br> 45<br> How long is BC?

wel

Answer:

6sqrt(2)=8.5

Step-by-step explanation:

Using pythagoras theorem

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3 years ago

URGENT What is the range of this function? HELP PICTURE BELOW

LenKa [72]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Algebra 1

BigorU [14]

Answer:

The expression is $4b^{6}c^{3}$ ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- In the exponent rules, we add the exponents when we multiply terms

have same base

- Ex: $a^{m}*a^{n}=a^{m+n}$

- The volume of the rectangular box is the product of its three

dimensions

* Lets solve the problem

- John buys a water tank from a company

- The tank he buys has the dimensions b² by b^4 by 4c³

∵ The water tank is shaped a rectangular box

∵ The tank has dimensions $b^{2},b^{4},4c^{3}$

∵ The volume of the tank = L × W × H , where L , W , H are the

dimensions of the tank

- Assume that L = b² , W = $b^{4}$ and H = 4c³

∴ The volume of the tank = b² × $b^{4}$ × 4c³

- b² and b^4 has the same base, then add its exponents

∴ The volume of the tank = $b^{4+2}$ × 4c³

∴ The volume of the tank = $b^{6}$ × 4c³

∴ The volume of the tank = $4b^{6}c^{3}$

* The expression which represents the volume of the tank is:

$4b^{6}c^{3}$

∴ The answer is the second expression

8 0

3 years ago

Given the Vertices of ΔABC are A (2, -5,) B (-4, 6) and C (3, 1), find the vertices following each of the transformations FROM T

oksano4ka [1.4K]

Answer:

I. A' = (5,-5), B' = (-1,6), C' = (6,1)

II. A' = (5,-11), B' = (-1,0), C' = (6,-5)

III. A' = (-5,-2), B = (6,4), C' = (1,-3)

Step-by-step explanation:

We are given the vertices of ΔABC as A = (2,-5), B = (-4,6) and C = (3,1).

I. It is required to 'reflect the triangle about the line x= 3'.

This rule changes (x,y) to (x+3,y).

So, the new vertices are given by,

A' = (2+3,-5) = (5,-5)

B' = (-4+3,6) = (-1,6)

C' = (3+3,1) = (6,1)

II. It is required to 'translate the triangle 3 units to the right and 6 units down'.

This rule changes (x,y) to (x+3,y-6).

So, the new vertices are given by,

A' = (2+3,-5-6) = (5,-11)

B' = (-4+3,6-6) = (-1,0)

C' = (3+3,1-6) = (6,-5)

III. It is required to 'rotate the triangle by 90° about the origin counter-clockwise'.

This rule changes (x,y) to (y,-x).

So, the new vertices are given by,

A = (2,-5) implies A' = (-5,-2)

B = (-4,6) implies B = (6,4)

C = (3,1) implies C' = (1,-3)

6 0

3 years ago