Answer:
Step-by-step explanation:
The question is incomplete since they do not give information about the Car type 3.
We will do it in a generic way, we will say that the Car type 3 has a mean of M and a standard deviation SD.
We would be:
P (CT3 <550) = P [z <(550 - X) / SD]
Now if we give it values, for example that X = 600 and SD = 120
It would remain:
P (CT3 <550) = P [z <(550 - 600) / 120]
P (CT3 <550) = P [z <-0.42]
We look for this value in the normal distribution table (attached) and it shows us that the probability is approximately 0.3372, that is, 33.72%
What you need to do is replace the X and SD values of theCar type 3 in the equation above how I just did and you will get the result.
Answer:
i dont understand sir sorry
Answer:
Z(2w-2)=24
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Answer:
1.60934 per hour
please mark me brainliest
Answer:
Options (2) and (3)
Step-by-step explanation:
Let, 
-8 + 8i√3 = a² + b²i² + 2abi
-8 + 8i√3 = a² - b² + 2abi
By comparing both the sides of the equation,
a² - b² = -8 -------(1)
2ab = 8√3
ab = 4√3 ----------(2)
a = 
By substituting the value of a in equation (1),
48 - b⁴ = -8b²
b⁴ - 8b² - 48 = 0
b⁴ - 12b² + 4b² - 48 = 0
b²(b² - 12) + 4(b² - 12) = 0
(b² + 4)(b² - 12) = 0
b² + 4 = 0 ⇒ b = ±√-4
b = ± 2i
b² - 12 = 0 ⇒ b = ±2√3
Since, a =
For b = ±2i,
a = 
= 
= 
But a is real therefore, a ≠ ±2i√3.
For b = ±2√3
a = 
a = ±2
Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)
Options (2) and (3) are the correct options.
