Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
There is no solution for the first one
if you eliminate y you get 2 equations
-13x - 13z = -25
-13x - 13x = -15
- there is no solution to theses
a23 means the element in the second row and the 3rd column
so its -5
The single transformation from shape A to B is: dilate A by 1/2, followed by a 180 degrees rotation
<h3>How to determine the transformation?</h3>
From the figure, we have:
- Shape A is twice the size of shape B
- Both shapes can be rotated by 180 degrees in either direction to map onto the other, after dilation.
This means that:
The scale of dilation from shape A is:
k = 1/2
Hence, the single transformation from shape A to B is: dilate A by 1/2, followed by a 180 degrees rotation
Read more about transformations at:
brainly.com/question/11707700
#SPJ1
Answer:
Step-by-step explanation:
3*(4x - 3) = 63 Divide both sides by 3
4x - 3 = 63/3
4x - 3 = 21 Add 3 to both sides
4x = 21 + 3
4x = 24 Divide by 4 on both sides
4x/4 = 24/4
x = 6
Note: The perimeter is the sum of all three sides. One side is 4x - 3 All 3 sides must be 3*(4x - 3)
A would be correct because:
1. you have $118 in the beginning, so 118
2. Then you gave a check of $9, so 118-9
3. Then you gave another check of $84.25, so 118-9-84.25
4. Then you put in $95, so 118 - 9 - 84 + 95.
