Answer:
see below
Step-by-step explanation:
The graph of it on a number line is an open circle at x=3 with a line extending to the right through larger numbers.
When the inequality does not include the "or equal to" case, the boundary is graphed as a dashed line (on an x-y plane) or open circle (on a number line). The shaded area covers values of the variable that meet the condition of the inequality. Here, those are values of x that are more than 3.
Yes 0.634 is a rational
number.
Rational numbers are those numbers that can be still expressed in
standard form or in fraction form and vice-versa. Unlike irrational numbers
that are opposed to the definition of rational numbers. These values include
pi, square root of two and etc. These values are impossible to fractionize.
To better illustrate this
circumstance.
We can have calculate a number that will have a quotient of 0.634
or a fraction that is equal to the given value.
<span><span>
1. </span><span> 634/1000 =
0.634</span></span>
<span><span>2. </span><span> 317/500 = 0.634
</span></span>
Answer:
35
Step-by-step explanation:
Since all the angles are the same in this triangle, all the sides should be the same too.
Hence, 3x - 5 = 4x - 30
5 + -1x = -30
-1x = -35
x = 35
Hope this helped!
Answer:
x=15 cm
Step-by-step explanation:
The two triangles in the diagram are:
ABC and BDC
First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.
Hypotenuse is the largest side of a triangle which is usually in front of the right angle.
So in BDC
![Base = BD =10cm\\Hypotenuse = BC = ?\\Perpendicular = CD = 2\sqrt{11}cm](https://tex.z-dn.net/?f=Base%20%3D%20BD%20%3D10cm%5C%5CHypotenuse%20%3D%20BC%20%3D%20%3F%5C%5CPerpendicular%20%3D%20CD%20%3D%202%5Csqrt%7B11%7Dcm)
Applying Pythagoras theorem:
![(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm](https://tex.z-dn.net/?f=%28Hypotenuse%29%5E2%20%20%3D%20%28Base%29%5E2%20%2B%20%28Perpendicular%29%5E2%5C%5CBC%5E2%20%3D%20BD%5E2%20%2B%20CD%5E2%5C%5CBC%5E2%20%3D%20%2810%29%5E2%20%2B%20%282%5Csqrt%7B11%7D%29%5E2%5C%5CBC%5E2%20%3D%20100%2B%282%5E2%20%2A%2011%29%5C%5CBC%5E2%20%3D%20100%2B%284%2A11%29%5C%5CBC%5E2%20%3D%20100%2B44%5C%5CBC%5E2%20%3D%20144%5C%5C%5Csqrt%7BBC%5E2%7D%20%3D%20%5Csqrt%7B144%7D%5C%5CBC%20%3D%2012cm)
Solving for triangle ABC
![Base = BC = 12 cm\\Perpendicular = AB = 9 cm\\Hypotenuse = AC = x\\](https://tex.z-dn.net/?f=Base%20%3D%20BC%20%3D%2012%20cm%5C%5CPerpendicular%20%3D%20AB%20%3D%209%20cm%5C%5CHypotenuse%20%3D%20AC%20%3D%20x%5C%5C)
Applying Pythagoras theorem
![AC^2 = BC^2+AB^2\\x^2 = (12)^2 + (9)^2\\x^2 = 144+81\\x^2 = 225\\\sqrt{x^2} = \sqrt{225}\\x = 15cm](https://tex.z-dn.net/?f=AC%5E2%20%3D%20BC%5E2%2BAB%5E2%5C%5Cx%5E2%20%3D%20%2812%29%5E2%20%2B%20%289%29%5E2%5C%5Cx%5E2%20%3D%20144%2B81%5C%5Cx%5E2%20%3D%20225%5C%5C%5Csqrt%7Bx%5E2%7D%20%3D%20%5Csqrt%7B225%7D%5C%5Cx%20%3D%2015cm)
Hence,
x=15 cm