These dot plots show the heights (in feet) from a sample of two different
1 answer:
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Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ
Use the Sum/Difference Identities:
sin(α + β) = sinα · cosβ + cosα · sinβ
cos(α - β) = cosα · cosβ + sinα · sinβ
Use the Unit circle to evaluate: sin45 = cos45 = √2/2
Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ
Use the Pythagorean Identity: cos²Ф + sin²Ф = 1
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<u>Proof LHS → RHS</u>
LHS: 2sin(45 + 2A) · cos(45 - 2A)
Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)
Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]
Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]
Distribute: cos²2A + 2cos2A·sin2A + sin²2A
Pythagorean Identity: 1 + 2cos2A·sin2A
Double Angle: 1 + sin4A
LHS = RHS: 1 + sin4A = 1 + sin4A
This question is incomplete. The attached image was obtained online
Answer:
41 square units
Step-by-step explanation:
Looking at diagram that was attached, we can see that the Polygon s the combination of a square and a triangle.
In square CDEF we have:
The lengths of the side of the square= 4 units
Hence, the area of square is: length ²
Area of square= 4²
=16 square units
Also, in ΔBFA we have:
The base of the triangle is calculated as
=6 + 4= 10 units
height of the triangle is: FA= 5 units
The formula for Area of a triangle = 1/2 × Base × Height
Hence, we have area of ΔBFA as:
= 1/2 × 10 × 5
Area= 25 square units
The Area of the Polygon = Area of the square + Area of the triangle
16 square units + 25 square units
= 41 square units
