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Maru [420]
3 years ago
8

What Is the domain of the function

Mathematics
1 answer:
serg [7]3 years ago
3 0
Domain is 0 <= x < 4
You might be interested in
5. 30 is 60% of what number
sergejj [24]

The answer is 50, 30 is 60% of 50.

4 0
3 years ago
What is the product of (3 + 5i) and (2 – 6i)? 6 – 30i 36 – 8i –24 – 8i –24 – 28i
Katyanochek1 [597]

Answer:

36 - 8i

Step-by-step explanation:

(3 + 5i)(2 - 6i) ← expand factors using FOIL

= 6 - 18i + 10i - 30i² → i² = - 1

= 6 - 8i + 30

= 36 - 8i

3 0
3 years ago
A community center is trying to raise $1680 to purchase exercise equipment. The center is hopping to receive equal contributions
goblinko [34]

Answer:

x = 1680 / N, where N is the number of people and x the amount each person has to give for equal contribution. So for N = 10 ==> x = 168.

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP!<br> WILL MARK BRAINLIEST!
RideAnS [48]

Answer:

1) 7m

2) 13

3) 4x^2y

4) 6s^3t^4

Step-by-step explanation:

gcf means the the greatest factor that works for both terms

1) 21m^3 and 28m

    let's first find the gcf for the coefficient

    21 and 28, the gcf is 7. (hopefully thats easy to explain)

    the gcf for the variables is the same mindset as the numbers

    m^3 and m, both can be factored by m

    so the gcf is 7 * m which is 7m

2)

  13x and 26

  let's first find the gcf for the coefficient

  13 and 26, gcf is 13

  there's only one variable, x, so there's not gcf for that

 so the gcf is just 13

3)

  8x^2y and -12x^3y^2

  let's first find the gcf for the coefficient

  8 and -12, the gcf is 4 (you can also say -4)

  for the variables , same mindset

 x^2y and x^3y^2

 the gcf for x is x^2, and for y it is just y

 so 4 * x^2 * y = 4x^2y

by understanding 3) hopefully you can understand 4)

pls comment for any questions

7 0
4 years ago
7x + 2y = 17<br>2x - 2y = 1<br>=​
DerKrebs [107]

Answer:

(2,\frac{3}{2}})

Step-by-step explanation:

For finding the system of equations you can use one of two methods. There's the elimination method and also the substitution method. For this I think the best way we could go at solving this is by using the elimination method. Since we can eliminate the 2y. We can then solve for x and then we'll go from there.

\left \{ +{{7x+2y=17} \atop {2x-2y=1}} \right. \\\\9x=18\\x=2

Now that we know what x is we can substitute it for one of the equations and then we will be able to solve for y.

7x+2y=17\\7(2)+2y=17\\14+2y=17\\2y=3\\y=\frac{3}{2}

So now we have the x and the y and once we place them together we can get the solution of those two equations, and the solution is (2,\frac{3}{2}}).

5 0
3 years ago
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