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2 years ago

6

the manufacture id number for del monte is (024000) and the item number for a can of gold and white corn is (02771). what is the

valid UPC?

1 answer:

dalvyx [7]2 years ago

4 0

Answer:A

Step-by-step explanation:

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Simplify the expression: –3(–7 + 3z)

aleksandrvk [35]

Hey there! I'm happy to help!

We want to multiply each term inside the parentheses by the number on the outside.

-3(-7)=21

-3(3z)=-9z

Therefore, our expression is 21-9z.

Now you know how to use the distributive property! Have a wonderful day! :D

5 0

2 years ago

How do you solve this (−18) ÷ 3 + (5)(−2) ?

Alekssandra [29.7K]

<span>(−18) ÷ 3 + (5)(−2)
Multiply 5 by -2
(-18)/3 -10
Divide -18 by 3
-5-10
Subtract 10 from -5
Final Answer: -15</span>

6 0

2 years ago

Find the value of this expression if x = 1 and<br> y = -7.<br> x^2y/-9

Dmitry [639]

Answer:

math is hard for me but yeah a good place to find answers is here or ggl maybe search on gg and the at the end put answer key i do that a lot hope my

Step-by-step explanation:

explanation helps

3 0

2 years ago

The expression 50 can be simplified to

puteri [66]

Answer:

25

Step-by-step explanation:

The first step in simplifying the expression of the square root of 50 involves finding factors of 50. This just means we are trying to find two whole numbers that, when multiplied, equal 50. Since 50 is an even number, 2 is going to be a factor, and so we can rewrite 50 as 2 times 25.

6 0

2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

2 years ago