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Margaret [11]
3 years ago
10

James bought 2/3 pound of red apples, 3/4 pound of green apples, and 5/6 pound of yellow apples. How many pounds of apples did J

ames buy altogether
Mathematics
1 answer:
Mariana [72]3 years ago
3 0
Ok, so we can't solve that because all of the fraction's denominators are different, so we need to find a common denominator for all of the fractions. The lowest common denominator is 12. So to get twelve we multiply the denominator and numerator to get the denominator. So in 3/4 we multiply the 4 by 3 and the 3, so we get 9/12. In 2/3 we multiply the 3 by 4 and the 2 by 4 and we get 8/12. Finally, in 5/6 you multiply the 6 by 2 to get 12, and the 5 by 2, and you get 10/12. So 10/12 + 8/12 + 9/12 = 27/12 = 2 3/12, or 2 1/4.
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What is the equation in point slope form of the point (2,-5) and (0,3)
Art [367]

7x-y-17=0

Step-by-step explanation:


3 0
3 years ago
An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect
Serggg [28]

Answer:

k = 1

P(x > 3y) = \frac{2}{3}

Step-by-step explanation:

Given

f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y  \leq x }  & { \text 0, { elsewhere. } } \end{array} \right.

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1

Where

{ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y  \leq x }

Substitute values for the interval of x and y respectively

So, we have:

\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1

Isolate k

k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1

Integrate y, leave x:

k \int\limits^2_{0} y {dx} \, [0,x/2]= 1

Substitute 0 and x/2 for y

k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1

k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1

Integrate x

k * \frac{x^2}{2*2} [0,2]= 1

k * \frac{x^2}{4} [0,2]= 1

Substitute 0 and 2 for x

k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1

k *[ \frac{4}{4} - \frac{0}{4} ]= 1

k *[ 1-0 ]= 1

k *[ 1]= 1

k = 1

Solving (b): P(x > 3y)

We have:

f(x,y) = k

Where k = 1

f(x,y) = 1

To find P(x > 3y), we use:

\int\limits^a_b \int\limits^a_b {f(x,y)}

So, we have:

P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy

P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy

P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0  dxdy

Integrate x leave y

P(x > 3y) = \int\limits^2_0  x [0,y/3]dy

Substitute 0 and y/3 for x

P(x > 3y) = \int\limits^2_0  [y/3 - 0]dy

P(x > 3y) = \int\limits^2_0  y/3\ dy

Integrate

P(x > 3y) = \frac{y^2}{2*3} [0,2]

P(x > 3y) = \frac{y^2}{6} [0,2]\\

Substitute 0 and 2 for y

P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}

P(x > 3y) = \frac{4}{6} -\frac{0}{6}

P(x > 3y) = \frac{4}{6}

P(x > 3y) = \frac{2}{3}

8 0
3 years ago
Rewrite x+2y=-4 in slope intercept
barxatty [35]

Answer:

y= - 1/2 x-2 ( SEE IMAGE BELOW)

Step-by-step explanation:

FYI you can use the app photo math, you just take a pic of the problem and it gives you the answer and explains the steps and it is free.

5 0
3 years ago
Read 2 more answers
72 is 45% of what number? Please give me a explanation with the answer asap
Juliette [100K]

Answer:

160

Step-by-step explanation:

72/45 = 1.6

1.6 * 45 = 72

Background information

160/100 = 1.6 (100 for percents)

160 fits the answer so it is right

HOPE THIS HELPS

PLZZ MARK BRAINLIEST

5 0
2 years ago
Suppose at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard. Also, 30% of the
Doss [256]

Answer:

0.6,0.7,0.3 neither disjoint nor independent.

Step-by-step explanation:

Given that at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard.

A= visa card

B = Master card

P(A) = 0.60 and P(B) = 0.40

P(AUB)' = 0.30

i.e. P(AUB) = 0.70

Or P(A)+P(B)-P(AB) =0.70

P(AB)= 0.30

Randomly select a student from the university.

1) the probability that this student does not have a MasterCard.

= P(B') = 1-0.4 =0.6

2.  the probability that this student has either a Visa card or a MasterCard.

=P(AUB) = 0.70

3. Calculate the probability that this student has neither a Visa card nor a MasterCard.

=P(AUB)' = 0.30

4. Are the events A and B disjoint? Are the events A and B independent?

A and B have common prob 0.30 hence not disjoint.

P(AB) ≠P(A)P(B)

Hence not independent

6 0
3 years ago
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