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zzz [600]
3 years ago
14

What are common factors of 10 and 5?

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
Factors of 5: 1, 5 factors of 10: 1, 2, 5, 10 we can see that that common factors of 5 and 10 are 1 and 5 because both of the numbers are factors of 5 and 10
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Please answer quick!
inessss [21]
The answer should be the 3rd one
5 0
3 years ago
Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm
VladimirAG [237]

Answer:

y=2x^2-4x-8

Step-by-step explanation:

<u>Factored form of a parabola</u>

y=a(x-p)(x-q)

where:

  • p and q are the x-intercepts.
  • a is some constant.

Given x-intercepts:

  • (1+√5, 0)
  • (1-√5, 0)

Therefore:

\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))

\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})

To find a, substitute the given point (4, 8) into the equation and solve for a:

\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8

\implies a(3-\sqrt{5})(3+\sqrt{5})=8

\implies4a=8

\implies a=2

Therefore, the equation of the parabola in factored form is:

\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})

Expand so that the equation is in standard form:

\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)

\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)

\implies y=2(x^2-2x-4)

\implies y=2x^2-4x-8

6 0
1 year ago
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monitta

Answer:

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Step-by-step explanation:

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2 years ago
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You need to memorize them for tests

Hope that helped!!! k

4 0
3 years ago
Read 2 more answers
Find the solution to 8a=24
DaniilM [7]
A=3 so 8*3=24.......................
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3 years ago
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