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Aleks04 [339]
3 years ago
7

Which equation is equivalent to 2^4x=8^x-3?

Mathematics
1 answer:
slavikrds [6]3 years ago
8 0

Answer:

D

Step-by-step explanation:

You might be interested in
X − 3 − 2(6 − 2x) = 2(2x − 5)
Finger [1]

Multiply the first bracket by -2

Multiply the second bracket by 2

x-3-12+4x= 4x-10

- negative number times + positive number= - negative number

- negative number times -negative number = + positive number

x+ 4x-3-12= 4x-10

5x-15= 4x-10

Move 4x to the other side

5x-4x-15= 4x-4x-10

x-15= -10

Move -15 to the other side

x-15+15= -10+15

x= 5

Answer : x= 5

7 0
3 years ago
Read 2 more answers
Suppose the polynomial f(x) has the following end behavior: as x approaches infinity, f(x) approaches infinity, and as x approac
galina1969 [7]

Answer:

C. x³+10x²−5x+5

E. 7x⁵+4x²

F. x+8

Step-by-step explanation:

The graph they described should look something like the one i drew below.

So all you have to do is look at the number with the highest exponent.

If the exponent is an odd number and the x is positive then that function will have an end behavior like the picture i posted.

x³ is good

-x³ is bad because of the negative sign

x² is bad because exponent is even

x⁷ is good

123x¹ is good

6 0
3 years ago
The answer is is 26, -44, but i dont understand how to solve it. can you explain?
Anna [14]
║a+9║/7=5
you multiply 7 on both sides which cancel out 7.
now it ║a=9║=35
and now it would be a+9=35 and a+9=-35 then solve it.
35-9 and 9-(-35)= 26 and -44
hope this helped!
4 0
3 years ago
Help me with a ASAP plz and explain
max2010maxim [7]

(f+g)(x)=f(x)+g(x)=(2x-6)+(4x+7)=6x+1

(f-g)(x)=f(x)-g(x)=(2x-6)-(4x+7)=-2x-13

(fg)(x)=f(x)×g(x)=(2x-6)(4x+7)=8x^2-10x-42

(f+g)(-2)=f(-2)+g(-2)=(2(-2)-6)+(4(-2)+7)=-11

4 0
3 years ago
In what quadrant will θ terminate, if sin θ is positive and sec θ is negative?
kow [346]
Sin x is possitive in two quadrants : 

quadrant I and quadrant II

in quadrant I, cos x is positive

in quadrant II , cos x is negative

so i think the answer is : quadrant II

hope this helps
5 0
3 years ago
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