Answer:
x=3X 2 + 5x -6
Step-by-step explanation:
3X2 + 5X-6= 3X2 + 5X 6
X=3X2 +5X -6
Given:

To find the vertical and horizontal asymptotes:
The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.
But, here there is no such point.
Thus, the function f(x) doesn't have a vertical asymptote.
The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

Thus, y = 0 is the horizontal asymptote for the given function.
Answer:
a^2 + 4a/b + 4/b^2
Step-by-step explanation:
Which of the following is equivalent to (a + b/2) ^2?
The formula of the distance between two points:

We have the points (-1, -10) and (-12, -3). Substitute:


Answer: d ≈ 13.0